Funksiyaning aniqlanish sohasi
Javoblar ota-onalar va o‘qituvchilar uchun.
1
y = √(3x + 12) funksiyaning aniqlanish sohasini toping.
x ≥ −4
2
y = 2 : (x² − 4) funksiyaning aniqlanish sohasini toping.
x ≠ 2 va x ≠ −2
3
y = √(x² − 6x + 8) funksiyaning aniqlanish sohasini toping.
x ≤ 2 yoki x ≥ 4
4
y = |x + 1| − 3 funksiyaning x = 2 dagi qiymatini va grafigining uchini toping.
y(2) = 0; uch (−1; −3)
5
y = 1 : √(x − 1) funksiya uchun nima uchun x = 1 aniqlanish sohasiga kirmaydi? Sohani yozing.
x − 1 > 0 bo‘lishi kerak (ildiz maxrajda va nolga teng bo‘lmasligi shart): x > 1.