☰ Contents · Chemistry

Aluminium compounds. Copper

Lessons 29–30 · 2 lessons · I.R. Asqarov, K. G‘opirov, N.X. To‘xtaboyev. Chemistry Grade 9, revised 4th edition. “O‘zbekiston” NMIU, Tashkent, 2019
29

Aluminium compounds and uses

Textbook: pp. 129–130
GoalKnow the amphoteric nature of aluminium oxide and hydroxide, alum, and the uses of aluminium compounds.
New words
amphoteric oxide · amfoter oksidaluminium hydroxide · aluminiy gidroksidalum · achchiqtoshcorundum · korund
Explanation

Al₂O₃ is a white, very hard, hard-to-melt substance; in nature it is the mineral corundum. It is amphoteric: it reacts with both acid and alkali: Al₂O₃ + 6HCl → 2AlCl₃ + 3H₂O and Al₂O₃ + 2NaOH + 3H₂O → 2Na[Al(OH)₄]. Al(OH)₃ is insoluble in water; we make it by adding alkali to a solution of an aluminium salt: AlCl₃ + 3NaOH → Al(OH)₃↓ + 3NaCl (a white gelatinous precipitate). With an excess of alkali the precipitate dissolves: Al(OH)₃ + NaOH → Na[Al(OH)₄], and with acid it gives a salt: Al(OH)₃ + 3HCl → AlCl₃ + 3H₂O. On heating the hydroxide decomposes: 2Al(OH)₃ → Al₂O₃ + 3H₂O. Alum KAl(SO₄)₂·12H₂O is used in dyeing fabrics, tanning leather and purifying water; corundum with Cr³⁺ impurity is ruby, with Fe and Ti ions it is sapphire.

Worked examples
Heating 156 g of Al(OH)₃ (2 mol, M = 78) gives 1 mol of Al₂O₃, i.e. 102 g: 2Al(OH)₃ → Al₂O₃ + 3H₂O.
Adding NaOH drop by drop to AlCl₃ solution first gives a white precipitate of Al(OH)₃; in excess NaOH the precipitate dissolves as Na[Al(OH)₄].
Class activity

Teacher demonstration: first a little and then excess NaOH is added to AlCl₃ solution and the formation and dissolving of the precipitate is observed. The teacher does it in goggles and gloves; do not work with alkali at home. You write the “precipitate” and “solution” stages in your notebook with equations.

Practice
1
Write two equations proving the amphoterism of Al₂O₃.
2
How many grams of Al₂O₃ form on heating 312 g of Al(OH)₃? (M(Al(OH)₃) = 78, M(Al₂O₃) = 102)
3
How do we prepare Al(OH)₃? Write the equation.
4
Why does the precipitate disappear when excess NaOH is added to AlCl₃ solution?