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Review of the Grade 8 course

Lessons 33 · 1 lessons · Sh.A. Alimov, A.R. Xalmukhamedov, M.A. Mirzaakhmedov. Algebra: textbook for Grade 8 of general secondary schools. Revised 4th edition. Tashkent: “O‘qituvchi”, 2019
33

Review of the Grade 8 Algebra course

Textbook: pp. 219–229
GoalReview the main topics of the Grade 8 algebra course: algebraic fractions, powers and roots, inequalities, quadratic equations, statistics and combinatorics.
New words
algebraic fraction · algebraik kasrsystem of inequalities · tengsizliklar sistemasidiscriminant · diskriminantmultiplication rule · ko‘paytirish qoidasi
Explanation

We close the year briefly. With algebraic fractions we first factor, bring to a common denominator and reduce; the denominator must not be zero. For rational exponents a^(m/n) = ⁿ√(aᵐ), the base is positive, and the properties are as for natural exponents. In inequalities, multiplying by a negative number reverses the sign; the solution of a system is the common part; |x| < a ⇔ -a < x < a. In a quadratic equation we compute D = b² - 4ac and find two roots if D > 0 and one if D = 0; Vieta’s theorem gives x₁ + x₂ = -p, x₁x₂ = q. In statistics we use the mean, mode, median and range, and in combinatorics the multiplication and addition rules.

Worked examples
(x/(x - 3) - 3/(x + 3)) · (x² - 9)/(x² + 9) = ((x(x + 3) - 3(x - 3))/(x² - 9)) · (x² - 9)/(x² + 9) = ((x² + 9)/(x² - 9)) · (x² - 9)/(x² + 9) = 1.
2x² - 7x + 3 = 0: D = 49 - 24 = 25, x = (7 ± 5)/4, x₁ = 3, x₂ = 1/2. |2x - 3| < 5: -5 < 2x - 3 < 5, -2 < 2x < 8, -1 < x < 4.
Class activity

“Year quiz”: teams pick one question from each chapter (fractions, roots, inequalities, quadratic equations, statistics, combinatorics), give it to another team and ask for an explained answer.

Practice
1
Solve the system {x - 3 > 0, 10 - 2x > 0}.
2
In how many ways can a leader and a deputy be chosen from 5 pupils?
3
Solve x² - 6x + 5 = 0 with Vieta’s theorem.
4
Why does √(x - 2) make sense for x ≥ 2?