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The biquadratic equation. Equations reducible to quadratic ones

Lessons 27 · 1 lessons · Sh.A. Alimov, A.R. Xalmukhamedov, M.A. Mirzaakhmedov. Algebra: textbook for Grade 8 of general secondary schools. Revised 4th edition. Tashkent: “O‘qituvchi”, 2019
27

The biquadratic equation. Equations reducible to quadratic equations

Textbook: pp. 156–162
GoalSolve a biquadratic equation by introducing a new variable; reduce fractional equations to quadratic ones and check the roots.
New words
biquadratic equation · bikvadrat tenglamanew variable · yangi o‘zgaruvchifractional equation · kasr tenglamaextraneous root · begona ildiz
Explanation

An equation of the form ax⁴ + bx² + c = 0 (a ≠ 0) is called a biquadratic equation. We reduce it to the quadratic equation at² + bt + c = 0 with the substitution x² = t. After finding t₁ and t₂ we solve x² = t₁ and x² = t₂: if t > 0 then x = ±√t, if t = 0 then x = 0, and if t < 0 there is no real root. In a fractional equation we multiply both sides by the common denominator to get an integral equation; values that make a denominator zero are extraneous roots, so every root found must be checked against the denominators.

Worked examples
x⁴ - 10x² + 9 = 0: x² = t, t² - 10t + 9 = 0, t₁ = 1, t₂ = 9. x² = 1 → x = ±1; x² = 9 → x = ±3. Answer: ±1, ±3.
1/(x - 1) + 2/(x + 1) = 1: (x + 1) + 2(x - 1) = x² - 1, x² - 3x = 0, x = 0 or x = 3. Since x ≠ ±1, both roots are valid.
Class activity

“Substitution workshop”: groups solve a biquadratic equation with t = x², then check every root in the original equation.

Practice
1
Solve x⁴ - 5x² + 4 = 0.
2
Solve x⁴ + 3x² + 2 = 0.
3
Solve x²/(x - 2) = 4/(x - 2).
4
Why must the roots of a fractional equation be checked?