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Vieta’s theorem. Factoring a quadratic trinomial

Lessons 26 · 1 lessons · Sh.A. Alimov, A.R. Xalmukhamedov, M.A. Mirzaakhmedov. Algebra: textbook for Grade 8 of general secondary schools. Revised 4th edition. Tashkent: “O‘qituvchi”, 2019
26

Vieta’s theorem. Factoring a quadratic trinomial into linear factors

Textbook: pp. 149–155
GoalKnow the reduced quadratic equation and Vieta’s theorem (and its converse); factor a quadratic trinomial into linear factors.
New words
reduced quadratic equation · keltirilgan kvadrat tenglamaVieta’s theorem · Viyet teoremasisum and product of roots · ildizlar yig‘indisi va ko‘paytmasiquadratic trinomial · kvadrat uchhad
Explanation

An equation x² + px + q = 0 with leading coefficient 1 is called a reduced quadratic equation; any quadratic equation can be brought to this form by dividing by a. Vieta’s theorem: if x₁ and x₂ are the roots of this equation, then x₁ + x₂ = -p and x₁ · x₂ = q. The converse: if x₁ + x₂ = -p and x₁x₂ = q, then x₁ and x₂ are the roots of x² + px + q = 0; hence roots can be found by guessing, and an equation can be built from given roots. A quadratic trinomial ax² + bx + c with roots x₁ and x₂ factors as a(x - x₁)(x - x₂).

Worked examples
x² - 9x + 20 = 0: x₁ + x₂ = 9, x₁x₂ = 20, so by choosing x₁ = 4, x₂ = 5. The reduced equation with roots -1 and 6: p = -(-1 + 6) = -5, q = -1 · 6 = -6, that is x² - 5x - 6 = 0.
The roots of 2x² - x - 3 are x₁ = 3/2, x₂ = -1: 2x² - x - 3 = 2(x - 3/2)(x + 1) = (2x - 3)(x + 1). If one root of x² + 7x + q = 0 is -2, then x₂ = -7 - (-2) = -5 and q = (-2) · (-5) = 10.
Class activity

“Root pairs”: the teacher gives a sum and a product (for example 7 and 12), pupils find the two roots and write the equation.

Practice
1
Find the sum and product of the roots of x² - 9x + 14 = 0 without solving.
2
Write the reduced quadratic equation with roots -2 and 5.
3
Factor x² - x - 12.
4
Why are the roots of opposite signs when q < 0?