Lessons 8 · 1 lessons · M. A. Mirzaahmedov, Sh. N. Ismailov, A. Q. Amanov (algebra and analysis), B. Q. Haydarov (geometry). Mathematics Grade 10, Parts 1 and 2, 1st edition. EXTREMUM PRESS, Tashkent, 2017
8
Simple and compound interest
Textbook, Part 1: pp. 48–52
GoalKnow the simple and compound interest formulas; calculate interest, final balance, initial loan, rate and term.
New words
interest rate · foiz stavkasisimple interest · oddiy foizcompound interest · murakkab foizfinal balance · yakuniy balans
Explanation
When money is lent, the borrower returns the loan C and pays an extra interest I; it depends on the loan, the term and the yearly interest rate r (in percent). With simple interest the yearly interest is always computed from the original C: I = C · r · n / 100, where n is the number of years (18 months = 1.5 years). With compound interest the interest earned at the end of each period is added to the balance and the next interest is computed from the new balance; after n years the final balance is A = C · (1 + r/100)ⁿ. If interest is added k times a year (half-yearly k = 2, quarterly k = 4, monthly k = 12), then A = C · (1 + r/(100k))^(kn). The compound interest payment is I = A − C. In one year both methods agree, but for n ≥ 2 compound interest is larger.
Worked examples
4 000 000 so‘m is lent for 2.5 years at 12% simple interest per year: I = 4 000 000 · 12 · 2.5 / 100 = 1 200 000 so‘m; the total returned is 5 200 000 so‘m.
10 000 000 so‘m at 10% compound interest for 2 years: after year 1 it is 11 000 000, after year 2 it is 11 000 000 · 1.1 = 12 100 000, i.e. A = 10 000 000 · 1.1² = 12 100 000; I = 2 100 000. Simple interest would give 2 000 000: the difference is that year 1’s interest earns interest in year 2.
Class activity
Mini-bank game: each pair plays “customer” and “banker”. The customer deposits an imaginary 1000 so‘m; one pair computes 3 years with simple interest, another with compound interest. Compare the results on the board and discuss the reason for the difference.
Practice
1
Write the final-balance formula for compound interest after n years; how does it change if interest is added k times a year?
A = C(1 + r/100)ⁿ; with k additions per year A = C(1 + r/(100k))^(kn).
2
3 000 000 so‘m is lent at 15% simple interest per year for 2 years. How many so‘m is the interest?
900000
3
20 000 so‘m is deposited at 5% compound interest per year for 2 years. What is the final balance in so‘m?
22050
4
Why does compound interest bring more than simple interest over 3 years at the same rate? Explain with 1000 so‘m and 10%.
Simple: 100 so‘m each year, total 1300. Compound: 1100, 1210, 1331: interest in years 2 and 3 is computed from the grown balance, so 1331 > 1300.