☰ Contents · Mathematics

Complex numbers and operations on them

Lessons 38 · 1 lessons · M. A. Mirzaahmedov, Sh. N. Ismailov, A. Q. Amanov (algebra and analysis), B. Q. Haydarov (geometry). Mathematics Grade 10, Parts 1 and 2, 1st edition. EXTREMUM PRESS, Tashkent, 2017
38

Complex numbers, operations on them, and representing a complex number

Textbook, Part 2: pp. 75–79
GoalKnow the imaginary unit and complex numbers in algebraic form, the operations (addition, subtraction, multiplication, division via the conjugate) and their representation in the plane.
New words
imaginary unit · mavhum birlikcomplex number · kompleks sonconjugate · qo‘shma sonreal and imaginary part · haqiqiy va mavhum qism
Explanation

The equation x² + 4 = 0 has no real solution, since the square of every real number is non-negative. So we introduce the symbol i with i² = −1 (the imaginary unit). A number a + bi with real a, b is a complex number; a is its real part Re(z) and b its imaginary part Im(z). Two complex numbers are equal when their real parts and their imaginary parts are equal separately; they cannot be compared with “<” or “>”. Addition and subtraction act separately on the real and imaginary parts; multiplication expands the brackets and uses i² = −1: (a + bi)(c + di) = (ac − bd) + (ad + bc)i. The conjugate of z = a + bi is z̄ = a − bi, and z · z̄ = a² + b² is real. For division we multiply numerator and denominator by the conjugate of the denominator. The number z = a + bi is shown in the plane as the point (a, b) (or the vector to it): Ox is the real axis and Oy is the imaginary axis.

Worked examples
(3 + 2i)(1 − 4i) = 3 − 12i + 2i − 8i² = 3 − 10i + 8 = 11 − 10i.
(5 + i)/(2 − i) = (5 + i)(2 + i) / ((2 − i)(2 + i)) = (10 + 5i + 2i + i²) / (4 + 1) = (9 + 7i)/5 = 9/5 + (7/5)i.
Class activity

In pairs mark z₁ = 3 + i and z₂ = 1 + 2i in the coordinate plane, draw their vectors and find the sum by the parallelogram rule; compare with (3 + i) + (1 + 2i) = 4 + 3i.

Practice
1
What is i² equal to?
2
Find (4 − 3i) + (−1 + 5i).
3
Compute (2 + i)(2 − i).
4
Why do we multiply by the conjugate of the denominator when dividing complex numbers?