☰ Contents · Physics

Surface tension problems and lab work

Lessons 36–37 · 2 lessons · P. Habibullayev, A. Boydedayev, A. Bahromov, K. Suyarov, J. Usarov, M. Yuldasheva. Physics Grade 9, revised and expanded 3rd edition. G‘afur G‘ulom Publishing House, Tashkent, 2019
37

Laboratory work: determining the surface tension coefficient of a liquid

Textbook: p. 103
GoalLab work: determine the surface tension coefficient with a dynamometer and wire frames.
New words
dynamometer · dinamometrwire frame · sim ramkamean value · o‘rtacha qiymatmeasurement error · o‘lchash xatosi
Explanation

The idea is simple: touch a wire frame to water and pull it up slowly. Just before the frame leaves the water, the dynamometer shows the frame’s weight F₁ plus the surface tension force, F₂ = F₁ + F. So the surface tension force is F = F₂ – F₁. If l is the length of the line along which water touches the wire (for thin wire, close to twice the frame’s perimeter, counting inner and outer sides), then σ = F/l. Repeat with triangle, square and circle frames, take the mean of the results and compare it with the table value 0.073 N/m for water. The work is done with clean water and a soft dynamometer under the teacher’s supervision; never pull beyond the dynamometer scale.

Worked examples
Frame weight F₁ = 0.050 N, just before leaving the water F₂ = 0.073 N. So F = 0.023 N.
Square frame with side 4 cm: perimeter 16 cm, l ≈ 2·0.16 = 0.32 m; σ = 0.023/0.32 ≈ 0.072 N/m, close to the table value.
Class activity

Make a table: frame shape, F₁, F₂, F, l, σ. Find σ for the three frames, calculate the mean and compare it with the table value, stating the relative error. Discuss why the result is distorted if the frame is greasy.

Practice
1
Why is F = F₂ – F₁ taken?
2
If F = 0.018 N and l = 0.25 m, what is σ?
3
Three measurements: σ = 0.070, 0.074 and 0.072 N/m. Find the mean.
4
Why does a soapy or greasy frame give a lower measured σ?