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Heat engines and their efficiency

Lessons 28–29 · 2 lessons · P. Habibullayev, A. Boydedayev, A. Bahromov, K. Suyarov, J. Usarov, M. Yuldasheva. Physics Grade 9, revised and expanded 3rd edition. G‘afur G‘ulom Publishing House, Tashkent, 2019
29

Working principle of heat engines

Textbook: pp. 83–85
GoalThe working principle of a heat engine (heater, working substance, cooler); the Carnot cycle; calculating efficiency.
New words
heater and cooler · isitkich va sovitkichworking substance · ishchi jismefficiency · foydali ish koeffitsiyenti (FIK)Carnot cycle · Karno sikli
Explanation

Every heat engine has three parts: a heater at temperature T₁ (it gives heat Q₁), a working substance (usually a gas) and a cooler at T₂ < T₁ (it takes heat Q₂). The working substance changes state in repeating cycles: it takes Q₁ from the heater, does work and gives the remaining Q₂ to the cooler. The useful work is A = Q₁ – Q₂ and the efficiency is η = A/Q₁ = (Q₁ – Q₂)/Q₁ (·100 %). Heat must always be given to the cooler (second law), so η < 1 always. The French engineer S. Carnot found the greatest efficiency for an ideal engine, whose cycle consists of two isotherms and two adiabats (the Carnot cycle): η_max = (T₁ – T₂)/T₁ (T in kelvins). To raise the efficiency, raise the heater temperature or lower the cooler temperature; if T₁ = T₂ the engine can do no work.

Worked examples
In one cycle a machine takes 2000 J from the heater and gives 1500 J to the cooler: A = 2000 – 1500 = 500 J; η = 500/2000 = 0.25 = 25 %.
For an ideal engine with T₁ = 500 K and T₂ = 300 K: η_max = (500 – 300)/500 = 0.4 = 40 %. The efficiency of a real engine is lower.
Class activity

Draw an engine scheme on the board: “heater → working substance → cooler” with arrows Q₁, A, Q₂. Groups insert numbers (e.g. Q₁ = 800 J, A = 200 J) and find Q₂ and η. The teacher keeps changing the numbers.

Practice
1
What is the definition and formula of efficiency?
2
An engine with efficiency 25 % takes 1600 J from the heater. How many joules is the useful work?
3
Heater 127 °C, cooler 27 °C. Maximum efficiency of an ideal engine (%)?
4
Why can no heat engine reach an efficiency of 100 %?