☰ Contents · Biology (Cytology and genetics)

Basics of genetics and Mendel’s laws

Lessons 47–48 · 2 lessons · A. Zikiryayev, A. To‘xtayev, I. Azimov, N. Sonin. Biology. Basics of Cytology and Genetics, Grade 9, revised and expanded 5th edition. “Yangiyul Poligraph Service”, Tashkent, 2019
48

Mendel’s laws. Monohybrid cross

Textbook: pp. 130–136
GoalExplain Mendel’s first and second laws, incomplete dominance, the test cross and the gamete purity hypothesis.
New words
dominant trait · dominant belgirecessive trait · retsessiv belgihomozygote / heterozygote · gomozigota / geterozigotaallelic genes · allel genlar
Explanation

G. Mendel (1865) crossed pea plants differing in one pair of traits (monohybrid cross) and counted the results quantitatively over generations; his laws were rediscovered in 1900 by H. de Vries, K. Correns and E. Tschermak. First law (uniformity of F1, dominance): crossing two different homozygotes gives an F1 that is all alike and shows only one parental trait: AA × aa → all Aa. Second law (segregation): crossing F1 heterozygotes gives in F2 a 3:1 phenotype ratio (¾ dominant, ¼ recessive) and a 1:2:1 genotype ratio (AA : Aa : aa); Aa × Aa → ¼ AA, ½ Aa, ¼ aa. In incomplete dominance the heterozygote shows an intermediate trait (four-o’clock red × white → pink), so in F2 both phenotype and genotype ratios are 1:2:1. An organism with the dominant phenotype may be AA or Aa; the test cross (× aa) tells: AA × aa → all dominant; Aa × aa → 1 : 1 (Aa : aa). Gamete purity hypothesis: in a hybrid the factors do not blend, each gamete receives only one of a pair of alleles (homologous chromosomes separate in meiosis); allelic genes are genes at the same position of homologous chromosomes that determine alternative forms of one trait.

Worked examples
Pea: yellow seed (A) is dominant over green (a). Aa × Aa → ¼ AA, ½ Aa, ¼ aa: 3 yellow : 1 green. With 1200 seeds in F2, about 1200 ÷ 4 × 3 = 900 yellow and 300 green.
Red four-o’clock (RR) × white (rr) → F1 all Rr, pink. F1 × F1 → ¼ RR (red), ½ Rr (pink), ¼ rr (white) = 1:2:1. Pink × white (Rr × rr) → ½ pink, ½ white.
Class activity

“Punnett square”. Draw a 2×2 grid in your notebook: father’s gametes (A, a) on top, mother’s gametes (A, a) at the side. Fill in the squares and write the ratios. Then repeat for Aa × aa.

Practice
1
State Mendel’s first law.
2
Write the genotype and phenotype ratios in F2 of Aa × Aa.
3
Heterozygous (yellow, Aa) peas were crossed with each other and gave 800 seeds. About how many are green (aa)?
4
Why do we find out the genotype of a yellow-seeded pea by a test cross?