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Combining several methods of factorization

Lessons 27 · 1 lessons · Sh.A. Alimov, O.R. Xolmuhamedov, M.A. Mirzaahmedov. Algebra, Grade 7, revised and expanded 5th edition. O‘qituvchi NMIU, Tashkent, 2017
27

Combining several methods of factorization

Textbook: pp. 119–124
GoalCombine several factoring methods; the sum and difference of cubes formulas.
New words
sum of cubes · kublar yig‘indisidifference of cubes · kublar ayirmasiorder of methods · usullar tartibicomplete factorization · to‘liq ajratish
Explanation

When factoring a polynomial we follow this order: 1) if there is a common factor, take it out of brackets; 2) try the short multiplication formulas; 3) otherwise try grouping. Sometimes the methods are applied one after another: 2x³ - 18x = 2x(x² - 9) = 2x(x - 3)(x + 3). We continue until the factors cannot be factored further. The new formulas are a³ + b³ = (a + b)(a² - ab + b²), the sum of cubes, and a³ - b³ = (a - b)(a² + ab + b²), the difference of cubes. They can be checked by multiplying out: (a + b)(a² - ab + b²) = a³ + b³. For example 27 + b³ = (3 + b)(9 - 3b + b²). The trinomial in the second bracket cannot be factored further.

Worked examples
2x³ - 18x = 2x(x² - 9) = 2x(x - 3)(x + 3): first the common factor, then the difference of squares.
x³ - 8y³ = x³ - (2y)³ = (x - 2y)(x² + 2xy + 4y²).
Class activity

“Chain of methods”: a polynomial is written on the board. Each group member in turn applies one method (taking out, formula, grouping), and the chain continues until the factors cannot be factored further.

Practice
1
Factor 3a² - 12 completely.
2
Factor 8m³ + 1.
3
Compute 7³ - 3³ with the formula (a - b)(a² + ab + b²).
4
Why do we take out the common factor first?