☰ Contents · Mathematics

Estimating products, perimeter and ways to find area; problem solving

Lessons 68–72 · 5 lessons · I.V. Repyova. Mathematics Grade 4, Parts 1–4. Novda Edutainment, Tashkent, 2023
65

Estimating values (practice)

Textbook: Part 2, lesson 65, pp. 81–83
GoalEstimating the lower and upper bounds of a product.
New words
factor · ko‘paytuvchiproduct · ko‘paytmalower bound · quyi chegaraupper bound · yuqori chegara
Explanation

To estimate a product we multiply round numbers smaller than each factor to get the lower bound and round numbers larger than each factor to get the upper bound. For 23 × 57 we get 20 × 50 = 1 000 and 30 × 60 = 1 800, so 1 000 < 23 × 57 < 1 800. Estimating helps find gross errors in a calculation.

Worked examples
46 × 27: lower 40 × 20 = 800, upper 50 × 30 = 1 500; exact 1 242.
For 67 × 48: 60 × 40 = 2 400 and 70 × 50 = 3 500; 2 016 is not in this range.
Class activity

“Spot the error”: the teacher writes wrong products and children find the mistake with bounds.

Practice
1
What is the lower bound (40 × 20) of the product 46 × 27?
2
What is the upper bound (50 × 30) of the product 46 × 27?
3
Someone says 67 × 48 = 2 016. The lower bound 60 × 40 is 2 400. Can this be right?
4
A room is 4 m 90 cm wide and 6 m 10 cm long. Estimate its area as 5 m × 6 m. How many m²?