☰ Contents · Mathematics

The ball chapter and stereometry review

Lessons 44–45 · 2 lessons · M. A. Mirzaahmedov, Sh. N. Ismailov, A. Q. Amanov (algebra and analysis), B. Q. Haydarov (geometry). Mathematics Grade 11, Parts 1 and 2, 1st edition. ZAMIN NASHR, Tashkent, 2018
44

Chapter review: sphere and ball

Textbook, Part 2: pp. 171–176
GoalReview the chapter on the ball and the sphere: solids inscribed in and circumscribed about a ball, and the relations between a ball, a cylinder and a cone.
New words
inscribed ball · ichki chizilgan sharcircumscribed ball · tashqi chizilgan shargreat circle · katta doiraArchimedes’ relation · Arximed munosabati
Explanation

Chapter formulas: ball V = (4/3)πR³, sphere S = 4πR², segment V = πh²(3R − h)/3, cap area 2πRh, sector V = ⅔πR²h. For a ball inscribed in a cube of edge a, r = a/2, and for a ball circumscribed about it, R = a√3/2. A cylinder circumscribed about a ball has height H = 2R and base radius R; then V_ball : V_cylinder = 2 : 3 and the surfaces (S_ball : S_total of the cylinder) are also 2 : 3 — Archimedes’ relation. For a cone (base radius r, height h, slant height l), the inscribed ball has radius ρ = rh/(r + l) (the incircle of the axial triangle) and the circumscribed ball has radius R = l²/(2h). If a polyhedron is inscribed in a ball, the centre is equidistant from all its vertices; if it is circumscribed about a ball, the centre is equidistant from all its faces. When solving, draw the axial section: in most cases the problem reduces to a plane problem about circles and triangles.

Worked examples
A ball of radius 3 is inscribed in a cylinder: r = 3, H = 6. V_cylinder = π · 9 · 6 = 54π, V_ball = 36π, ratio 2 : 3. S_total of the cylinder = 2π · 3 · (3 + 6) = 54π, S_ball = 36π, ratio also 2 : 3.
A cone has r = 6, h = 8, l = 10. The inscribed ball has ρ = 6 · 8/(6 + 10) = 3; the circumscribed ball has R = 100/16 = 25/4. Check: the centre is on the axis at distance R = 6.25 from the apex, and its distance to the base circle is √(6² + (8 − 6.25)²) = √(36 + 3.0625) = √39.0625 = 6.25.
Class activity

“Ball in a cube”: make a cardboard model of a cube with edge 8 cm (an adult helps with scissors) and fit a plasticine ball of diameter 8 cm inside. Calculate that the ratio of the ball’s volume to the cube’s volume is π/6 ≈ 52 % and compare with the amount of plasticine needed to fill the remaining space.

Practice
1
Find the volume of the ball inscribed in a cube of volume 64.
2
Find the surface of the ball circumscribed about a cube of edge 6.
3
A cone has r = 3, h = 4 (l = 5). Find the radius of the inscribed ball.
4
Why does a cylinder circumscribed about a ball have height 2R and base radius R?