☰ Contents · Mathematics

Cartesian coordinates in space

Lessons 16 · 1 lessons · M. A. Mirzaahmedov, Sh. N. Ismailov, A. Q. Amanov (algebra and analysis), B. Q. Haydarov (geometry). Mathematics Grade 11, Parts 1 and 2, 1st edition. ZAMIN NASHR, Tashkent, 2018
16

Cartesian coordinates in space

Textbook, Part 1: pp. 113–121
GoalLearn the rectangular Cartesian coordinate system in space, the coordinates of a point, the formulas for the distance between two points, the midpoint of a segment and the point dividing a segment in a given ratio, and the equations of a sphere and a ball.
New words
coordinate planes · koordinata tekisliklariz-coordinate (applicate) · applikataoctant · oktantequation of a sphere · sfera tenglamasi
Explanation

In space we take three mutually perpendicular axes Ox, Oy, Oz meeting at O; they determine the coordinate planes Oxy, Oyz, Oxz and divide space into 8 octants. Every point A is given by three numbers — the abscissa x, ordinate y and applicate z: A(x, y, z). Points on the Oz axis have the form (0, 0, c) and points of the plane Oxy have the form (x, y, 0). The distance between A(x₁, y₁, z₁) and B(x₂, y₂, z₂) is AB = √((x₂ − x₁)² + (y₂ − y₁)² + (z₂ − z₁)²) (the Pythagorean theorem applied twice). The midpoint of AB is ((x₁ + x₂)/2, (y₁ + y₂)/2, (z₁ + z₂)/2); the point P dividing AB in the ratio AP : PB = λ has coordinates (x₁ + λx₂)/(1 + λ), (y₁ + λy₂)/(1 + λ), (z₁ + λz₂)/(1 + λ). The sphere with centre (a, b, c) and radius R has the equation (x − a)² + (y − b)² + (z − c)² = R², and the ball is the inequality (x − a)² + (y − b)² + (z − c)² ≤ R². The distance from A(x, y, z) to the plane Oxy is |z|, and to the Ox axis √(y² + z²).

Worked examples
A(1, −2, 3) and B(4, 2, 15): AB = √(3² + 4² + 12²) = √(9 + 16 + 144) = √169 = 13. The midpoint is M((1 + 4)/2, (−2 + 2)/2, (3 + 15)/2) = (2.5, 0, 9). The point P with AP : PB = 1 : 2 (λ = 1/2): x = (1 + 2)/1.5 = 2, y = (−2 + 1)/1.5 = −2/3, z = (3 + 7.5)/1.5 = 7.
The sphere with centre (2, −1, 0) and radius 4: (x − 2)² + (y + 1)² + z² = 16. The point (2, −1, 4) lies on it: 0 + 0 + 16 = 16. For (3, 1, 1) we get 1 + 4 + 1 = 6 < 16, so it lies inside the ball.
Class activity

“Room coordinates”: take one corner of the classroom as the origin and the three lines where two walls and the floor meet as the axes. With a tape measure (with an adult’s help) find the coordinates in metres of a desk, a lamp and a door handle, compute the distance between two objects with the formula and compare it with the tape measurement.

Practice
1
Find the distance between (0, 0, 0) and (2, 3, 6).
2
Find the midpoint of the segment A(−4, 2, 6), B(2, 8, −2).
3
Write the equation of the sphere with centre (1, 0, −3) and radius 2.
4
Why is the distance from (3, 4, 5) to the plane Oxy equal to 5 but the distance to the Ox axis is not 5?