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Algebra and analysis review

Lessons 37 · 1 lessons · M. A. Mirzaahmedov, Sh. N. Ismailov, A. Q. Amanov (algebra and analysis), B. Q. Haydarov (geometry). Mathematics Grade 11, Parts 1 and 2, 1st edition. ZAMIN NASHR, Tashkent, 2018
37

Review of algebra and analysis

Textbook, Part 2: pp. 97–103
GoalReview the algebra and analysis course: equations and inequalities, exponential, logarithmic and trigonometric problems, progressions, derivatives and integrals.
New words
domain · aniqlanish sohasiprogression · progressiyacritical point · kritik nuqtaantiderivative · boshlang‘ich funksiya
Explanation

When solving an equation first write the domain: an expression under a logarithm is positive, a denominator is not zero, an expression under an even root is not negative; then check the roots you find against it. An exponential equation is brought to the same base (aˣ = aʸ ⟹ x = y); a logarithmic equation is solved with logₐ f = logₐ g ⟹ f = g or by the definition. In an arithmetic progression aₙ = a₁ + (n − 1)d and Sₙ = (a₁ + aₙ)n/2; in a geometric progression bₙ = b₁qⁿ⁻¹ and Sₙ = b₁(qⁿ − 1)/(q − 1). Derivatives: (xⁿ)′ = nxⁿ⁻¹, (sin x)′ = cos x, (eˣ)′ = eˣ, (ln x)′ = 1/x, and for a composite function we multiply by the derivative of the inner function. An extremum occurs where f′(x) = 0 and the sign changes; the tangent is y = f(a) + f′(a)(x − a). Integrals: ∫xⁿdx = xⁿ⁺¹/(n + 1) + C, ∫cos x dx = sin x + C, the definite integral ∫ₐᵇf dx = F(b) − F(a), and the area is ∫(upper − lower)dx. In an exam check each answer by substituting back or with a sketch.

Worked examples
Solve log₂(x + 1) + log₂(x − 1) = 3. Domain: x > 1. Combine into a product: log₂(x² − 1) = 3, x² − 1 = 8, x = ±3. The root x = −3 is outside the domain, so x = 3. Check: log₂4 + log₂2 = 2 + 1 = 3.
Investigate f(x) = x³ − 3x². f′(x) = 3x² − 6x = 3x(x − 2): critical points 0 and 2. At x = 0 the sign of f′ changes from + to −: a maximum f(0) = 0; at x = 2 from − to +: a minimum f(2) = −4. The tangent at x = 1: f(1) = −2, f′(1) = −3, so y = −2 − 3(x − 1) = −3x + 1.
Class activity

“Mistake detective”: give a friend three “solved” problems, each with one error (a spurious root kept in a logarithmic equation, the inner derivative 2 forgotten in the derivative of (2x + 1)³, a wrong number of terms in a progression sum). The friend finds and fixes the errors, then you swap roles.

Practice
1
Solve 3^(2x − 1) = 27.
2
In an arithmetic progression a₁ = 3 and d = 4. Find the sum of the first 10 terms.
3
Compute ∫₀¹ (6x² + 2x) dx.
4
Why must the roots be checked after solving a logarithmic equation?