☰ Contents · Physics

Semiconductor devices

Lessons 44–45 · 2 lessons · N. Sh. Turdiyev, K. A. Tursunmetov, A. G. Ganiyev, K. T. Suyarov, J. E. Usarov, A. K. Avliyoqulov. Physics Grade 10, 1st edition. Niso Poligraf Publishing House, Tashkent, 2017
45

Laboratory work: studying the current–voltage characteristic of a semiconductor diode

Textbook: pp. 166–167
GoalKnow the procedure for measuring the current–voltage characteristic of a semiconductor diode, its graph and the difference between forward and reverse connection.
New words
current–voltage characteristic · volt-amper xarakteristikaforward bias · to‘g‘ri ulanishreverse bias · teskari ulanishrheostat · reostat
Explanation

The aim is to study the dependence I(U) of a diode. Equipment: a diode, a low-voltage DC source (a safe value set by the teacher, usually not above 6–12 V), a milliammeter, a voltmeter, a rheostat connected as a potentiometer, a protective resistor (to limit the current in forward bias), a switch, wires. Procedure: 1) assemble the circuit and show it to the teacher; 2) set the rheostat slider to U = 0; 3) close the switch and raise the voltage in steps of 0.1 V, noting U and I each time; in forward bias the current must not exceed the value in the diode’s datasheet; 4) swap the source terminals (diode reversed) and measure U and I, never exceeding the datasheet’s maximum reverse voltage; 5) plot the graph for both directions. Result: in the forward direction the graph is not linear – for silicon the current rises sharply above ≈ 0.6–0.7 V; in the reverse direction the current is very small (a few μA) because only minority carriers pass.

Worked examples
A silicon diode in the forward direction: U = 0.5 V gives I ≈ 0.1 mA, 0.6 V gives 2 mA, 0.7 V gives 20 mA. Raising the voltage by 0.1 V makes the current 10 times larger – a very steep (exponential) graph. The resistance U/I falls: 5 kΩ → 300 Ω → 35 Ω.
In the reverse direction U = 10 V gives I = 5 μA: resistance U/I = 10/0.000005 = 2·10⁶ Ω = 2 MΩ. With 20 mA at 0.7 V forward, the one-way ratio is 2 MΩ / 35 Ω ≈ 6·10⁴.
Class activity

Only under the teacher’s supervision and at low voltage: carry out the work; never exceed the datasheet reverse voltage; never apply forward voltage without the protective resistor. Do not use a 36–42 V supply; follow the school’s safety rules.

Practice
1
Compare the forward and reverse branches of a diode characteristic.
2
U = 2 V, I = 4 mA. What is the resistance U/I (Ω)?
3
Why is a resistor placed in series with a forward-biased diode?
4
Why is a diode’s graph not a straight line?