☰ Contents · Physics

Work, energy and the conservation law

Lessons 14 · 1 lessons · N. Sh. Turdiyev, K. A. Tursunmetov, A. G. Ganiyev, K. T. Suyarov, J. E. Usarov, A. K. Avliyoqulov. Physics Grade 10, 1st edition. Niso Poligraf Publishing House, Tashkent, 2017
14

Energy and work. The law of conservation of energy. Work done when a body moves along an inclined plane

Textbook: pp. 47–50
GoalCalculate mechanical work, kinetic and potential energy, use the law of conservation of mechanical energy and find the work on an inclined plane.
New words
mechanical work · mexanik ishtotal mechanical energy · to‘la mexanik energiyaconservative force · konservativ kuchefficiency · foydali ish koeffitsiyenti (FIK)
Explanation

Energy is the quantitative measure of different forms of motion and interaction; its unit is 1 J. The scalar product of a force and the displacement is the mechanical work: A = F·s·cosα, where α is the angle between the force and the displacement. For α < 90° the work is positive, for α > 90° negative, for α = 90° zero. The work of gravity depends not on the shape of the path but only on the difference of heights: A = mg(h₁ – h₂); such forces are called potential (conservative), and on a closed path their work is zero. Kinetic energy is Eₖ = mυ²/2, potential energy Eₚ = mgh, total mechanical energy E = Eₖ + Eₚ. In a closed system where only conservative forces do work, E = const – the law of conservation of mechanical energy; in general energy is neither lost nor created, it only passes from one form to another. Efficiency η = Aᵤ/Aₜ·100%, where Aᵤ is the useful work and Aₜ the total work; friction makes η < 100%. An inclined plane gives a gain in force but none in work (the “golden rule of mechanics”). Raising a load m uniformly up an incline of length l and height h, the useful work is mgh, the total work is mgh(1 + μ·cotα) and η = 1/(1 + μ·cotα).

Worked examples
Force F = 50 N, displacement s = 4 m, angle between them 60° (cos60° = 0.5): A = 50·4·0.5 = 100 J. With 90° the work is zero (for example, gravity does no work when a load is carried horizontally).
We pull a 10 kg load along an incline 5 m long and 3 m high (sinα = 0.6; cosα = 0.8; μ = 0.25; g = 10 m/s²). The pulling force is F = mg(sinα + μcosα) = 100·0.8 = 80 N; total work 80·5 = 400 J; useful work mgh = 100·3 = 300 J; η = 300/400 = 75%.
Class activity

Only with the teacher: in class let a light cart roll down an inclined board, vary the release height and predict how its speed depends on the height (υ² ~ h). Put a stopper at the end of the board so the cart does not fall.

Practice
1
What is the formula for mechanical work and what does the angle α mean?
2
A force F = 40 N moves a body 5 m along its own direction. What is the work (J)?
3
A stone is thrown up from the ground at 20 m/s (g = 10 m/s²). Use energy conservation to find the maximum height (m).
4
An engine uses 1200 J of energy and does 300 J of useful work. What is the efficiency in per cent?
5
Why can efficiency never exceed 100%?