☰ Contents · Physics

Adiabatic process and the Carnot cycle

Lessons 28 · 1 lessons · N. Sh. Turdiyev, K. A. Tursunmetov, A. G. Ganiyev, K. T. Suyarov, J. E. Usarov, A. K. Avliyoqulov. Physics Grade 10, 1st edition. Niso Poligraf Publishing House, Tashkent, 2017
28

Adiabatic process. Efficiency of a heat engine. The Carnot cycle

Textbook: pp. 102–105
GoalKnow the adiabatic process, the working principle of a heat engine, efficiency and the Carnot cycle, and solve efficiency problems.
New words
adiabatic process · adiabatik jarayonheater and cooler · isitkich va sovitkichCarnot cycle · Karno sikliefficiency of a heat engine · issiqlik mashinasining FIK
Explanation

A process with no heat exchange with the surroundings is adiabatic (Q = 0); fast processes are close to it. From the first law A = –ΔU: if the gas expands and does work its internal energy falls and it cools; if it is compressed quickly it heats up. A heat engine converts the internal energy of fuel into mechanical work; it has three parts: a working substance (gas or steam), a heater (T₁) and a cooler (T₂). In one cycle the working substance takes heat Q₁ from the heater, gives Q₂ to the cooler and does work A = Q₁ – Q₂. The efficiency is η = A/Q₁ = (Q₁ – Q₂)/Q₁ (×100% for percent). The Carnot cycle is an ideal reversible cycle of two isotherms and two adiabats; its efficiency does not depend on the working substance: η = (T₁ – T₂)/T₁, with temperatures in kelvin (T = t + 273). So to raise the efficiency one raises T₁ and lowers T₂; the efficiency is always below 1 (100%). Carnot’s theorem: for given T₁ and T₂ no engine has an efficiency greater than that of the Carnot cycle.

Worked examples
An engine takes 600 kJ from the heater and gives 450 kJ to the cooler: A = 600 – 450 = 150 kJ; η = 150/600 = 0.25 = 25%.
A Carnot engine: heater 527 °C (T₁ = 800 K), cooler 27 °C (T₂ = 300 K). η = (800 – 300)/800 = 500/800 = 0.625 = 62.5%. If the cooler is at 227 °C (500 K), η = 300/800 = 37.5%.
Class activity

Only with the teacher: close the outlet of a bicycle pump with a finger, press the piston quickly and notice that the cylinder warms slightly (adiabatic compression). Let it cool afterward; do not heat it.

Practice
1
What is the efficiency formula of the Carnot cycle and in what unit is T?
2
A machine takes Q₁ = 800 J and gives Q₂ = 600 J. What is the efficiency in percent?
3
A Carnot engine: T₁ = 600 K, T₂ = 300 K. What is the efficiency in percent?
4
Why can a real engine not have an efficiency of 100%?