☰ Contents · Physics

Ohm’s law for a complete circuit

Lessons 37 · 1 lessons · N. Sh. Turdiyev, K. A. Tursunmetov, A. G. Ganiyev, K. T. Suyarov, J. E. Usarov, A. K. Avliyoqulov. Physics Grade 10, 1st edition. Niso Poligraf Publishing House, Tashkent, 2017
37

Ohm’s law for a complete circuit. Efficiency of a current source

Textbook: pp. 138–140
GoalApply extraneous forces, EMF, Ohm’s law for a complete circuit, short circuit and the efficiency of a current source in problems.
New words
extraneous forces · chet kuchlarelectromotive force (EMF) · elektr yurituvchi kuch (EYuK)internal resistance · ichki qarshilikshort circuit · qisqa tutashuv
Explanation

The electrostatic field does no work when a charge goes around a closed loop, so a circuit needs a source of energy based on forces of non-electrostatic nature – extraneous forces (chemical in a battery, magnetic in a generator). The work done by the extraneous forces in moving a unit positive charge inside the source is the electromotive force (EMF) of the source: ℰ = Aext/q, with unit volt. From conservation of energy we get Ohm’s law for a complete circuit: I = ℰ/(R + r), where R is the external and r the internal resistance of the source. Hence ℰ = IR + Ir; the voltage across the terminals is U = IR = ℰ – Ir. In an open circuit (I = 0) U = ℰ; with R = 0 (short circuit) the current is greatest, Isc = ℰ/r – very dangerous, the wires and source overheat. The efficiency of a source is η = Auseful/Aext = R/(R + r) = U/ℰ (×100% for percent); the larger R is, the higher the efficiency.

Worked examples
ℰ = 12 V, r = 1 Ω, R = 5 Ω: I = ℰ/(R + r) = 12/6 = 2 A; U = IR = 10 V (check: ℰ – Ir = 12 – 2 = 10 V); η = U/ℰ = 10/12 ≈ 83%.
A battery has ℰ = 4.5 V, r = 1.5 Ω. Short-circuit current I = ℰ/r = 4.5/1.5 = 3 A. With R = 13.5 Ω: η = R/(R + r) = 13.5/15 = 0.9 = 90%.
Class activity

Only by calculation: for a source ℰ = 9 V, r = 1 Ω make a table of I, U and η at R = 1, 2, 4, 8, 17 Ω and find at which R the efficiency is greatest. Never short-circuit batteries!

Practice
1
Write Ohm’s law for a complete circuit.
2
ℰ = 10 V, r = 2 Ω, R = 3 Ω. What is the current (A)?
3
What is the voltage at the source terminals in the same circuit (V)?
4
ℰ = 6 V, r = 0.5 Ω. What is the short-circuit current (A)? Why is it dangerous?