☰ Contents · Physics

Ammeter, voltmeter and measuring a source

Lessons 39–40 · 2 lessons · N. Sh. Turdiyev, K. A. Tursunmetov, A. G. Ganiyev, K. T. Suyarov, J. E. Usarov, A. K. Avliyoqulov. Physics Grade 10, 1st edition. Niso Poligraf Publishing House, Tashkent, 2017
40

Laboratory work: determining the EMF and internal resistance of a current source

Textbook: pp. 147–148
GoalKnow the procedure for finding the EMF and internal resistance of a current source with an ammeter and a voltmeter and calculating the results.
New words
EMF · EYuKinternal resistance · ichki qarshilikswitch · uzib-ulagichexternal resistance · tashqi qarshilik
Explanation

The aim is to measure ℰ and r of a source. Equipment: a low-voltage source (a battery or school supply, not above 6 V), an ammeter, a voltmeter, a switch, a rheostat or 10 Ω and 20 Ω resistors, wires. Procedure: 1) assemble the circuit (voltmeter in parallel with the terminals, ammeter in series with the external resistance) and show it to the teacher; 2) with the switch open the voltmeter reading U₀ ≈ ℰ (the voltmeter resistance is much greater than the internal resistance); 3) close the switch, read the ammeter I and the voltmeter U, and open the switch immediately (so the source does not run down); 4) from Ohm’s law ℰ = U + Ir, so r = (ℰ – U)/I; 5) repeat with another resistance and average the results. Sources of error: instrument accuracy, contact resistance, heating of the source. Never short-circuit the source.

Worked examples
Switch open: U₀ = 6 V (ℰ = 6 V). With 10 Ω: I = 0.5 A, U = 5 V: r = (6 – 5)/0.5 = 2 Ω.
With 28 Ω: I = 0.2 A, U = 5.6 V: r = (6 – 5.6)/0.2 = 2 Ω – the same in both measurements, so the result is reliable. The short-circuit current would be ℰ/r = 3 A (never produced in the experiment!).
Class activity

Only under the teacher’s supervision: assemble the circuit, close the switch only while reading, record U₀, U, I, ℰ, r in a table. Never use the mains (220 V) on your own.

Practice
1
Why does the voltmeter show the EMF when the switch is open?
2
ℰ = 4 V, U = 3.5 V, I = 0.25 A. What is r (Ω)? (r = (ℰ – U)/I)
3
ℰ = 9 V, r = 3 Ω. What is the short-circuit current (A)?
4
Why must the switch be opened after each reading?