☰ Contents · Geometry

Applications of the theorems; dot product

Lessons 30–31 · 2 lessons · B. Xaydarov, E. Sariqov, A. Qo‘chqorov. Geometry, Grade 9 (textbook for general secondary schools), revised 4th edition. Huquq va Jamiyat Publishing, Tashkent, 2019
30

Some applications of the laws of sines and cosines

Textbook: pp. 88–89
GoalApplications of the laws of cosines and sines: classify a triangle without finding angles, Heron's formula and R = abc/(4S).
New words
acute · o‘tkir burchakliobtuse · o‘tmas burchakliHeron's formula · Geron formulasisemi-perimeter · yarim perimetr
Explanation

Let a be the longest side. If b² + c² > a², the cosine is positive, so the triangle is acute; if b² + c² = a², it is right-angled; if b² + c² < a², it is obtuse. A right or obtuse angle always lies opposite the longest side. From S = ½bc·sinA and the law of sines, sinA = a/(2R), we get S = abc/(4R), that is R = abc/(4S). When three sides are given the area comes from Heron's formula: with semi-perimeter p = (a + b + c)/2, S = √(p(p − a)(p − b)(p − c)). So from three sides we can find the area, and then the circumradius, without finding any angle.

Worked examples
Sides 6, 7, 9: 6² + 7² = 85 > 81 = 9², so the triangle is acute. Sides 5, 6, 9: 25 + 36 = 61 < 81, so it is obtuse.
7, 15, 20: p = 21, S = √(21·14·6·1) = √1764 = 42; R = 7·15·20/(4·42) = 2100/168 = 25/2.
Class activity

“Quick type check”: cards show three numbers; students compare squares only (no angles) to decide the triangle type and hold up the result.

Practice
1
What kind of triangle has sides 8, 15, 17?
2
What is the circumradius of a triangle with sides 3, 4, 5?
3
What is the semi-perimeter p of a triangle with sides 9, 10, 17?
4
Why is the obtuse angle of a triangle always opposite the longest side?