Lessons 22–23 · 2 lessons · P. Habibullayev, A. Boydedayev, A. Bahromov, K. Suyarov, J. Usarov, M. Yuldasheva. Physics Grade 9, revised and expanded 3rd edition. G‘afur G‘ulom Publishing House, Tashkent, 2019
23
The first law of thermodynamics
Textbook: pp. 67–69
GoalState the first law of thermodynamics Q = ΔU + A and apply it to isothermal, isobaric, isochoric and adiabatic processes.
New words
first law of thermodynamics · termodinamikaning birinchi qonuniadiabatic process · adiabatik jarayonlaw of conservation of energy · energiyaning saqlanish qonunithermal insulation · issiqlik izolyatsiyasi
Explanation
Energy is neither created nor destroyed, it only changes from one kind to another; the first law of thermodynamics is this law applied to heat phenomena (R. Mayer, H. Helmholtz, J. Joule, mid-19th century). The heat given to a system is spent on changing its internal energy and on doing work against external forces: Q = ΔU + A. In an isothermal process T = const, ΔU = 0, so Q = A. In an isobaric process Q = ΔU + pΔV. In an isochoric process A = 0, so Q = ΔU. In an adiabatic process, with no heat exchange with the surroundings, Q = 0 and A = –ΔU: when the gas expands, the work is done at the expense of internal energy and the gas cools; when compressed it warms. Fast processes (compressing air in a pump, expansion of rising air and cloud formation) are close to adiabatic. A thermos flask is close to adiabatic insulation.
Worked examples
A gas received 500 J of heat and did 200 J of work: ΔU = Q – A = 500 – 200 = 300 J – the gas warmed.
A gas is compressed adiabatically and external forces do 400 J of work (A = –400 J, Q = 0): ΔU = –A = +400 J. The internal energy rises and the gas warms (a bicycle pump gets hot).
Class activity
Study the structure of a thermos (with an adult): inner and outer walls, an evacuated gap between them, a reflective coating. Why does hot tea stay hot for long? Draw and explain. An adult helps with opening and with pouring boiling water.
Practice
1
State the first law of thermodynamics and write its formula.
The heat given is spent on changing the internal energy and doing work: Q = ΔU + A.
2
An ideal gas receives 800 J of heat in an isothermal process. How much work does it do (J)?
800
3
A gas receives 4200 J of heat and its internal energy rises by 2700 J. How many joules of work does it do?
1500
4
Why does a gas cool when it expands adiabatically?
Q = 0 and the gas does work: A = –ΔU, so internal energy and temperature fall.