☰ Contents · Chemistry (Organic chemistry)

Isomerism and preparation of alkenes

Lessons 12 · 1 lessons · A. Mutalibov, E. Murodov, S. Masharipov, H. Islomova. Organic Chemistry, Grade 10, 1st edition. G‘afur G‘ulom Publishing House, Tashkent, 2017
12

Isomerism and preparation of alkenes

Textbook: pp. 44–50
GoalDistinguish the isomerism types of alkenes (chain, position, geometric) and write methods of preparing alkenes.
New words
position isomerism · holat izomeriyasicis-isomer · sis-izomerdehydration · degidratlanishdehydrohalogenation · degidrogalogenlanish
Explanation

Alkenes show three kinds of isomerism. Chain isomerism: butene-1 and 2-methylpropene. Position isomerism: the place of the double bond differs, e.g. butene-1 and butene-2, pentene-1 and pentene-2. Geometric isomerism: there is no rotation about the double bond, so if each double-bonded carbon carries two different substituents they lie on the same side (cis-) or opposite sides (trans-); cis- and trans-butene-2 are separate substances with different properties. For more complex substituents the Z/E system is used: the larger groups on the same side is Z, on opposite sides is E. Methods of preparation: (1) heating an alcohol with concentrated H₂SO₄ above 140 °C: C₂H₅OH → C₂H₄ + H₂O; (2) dehydrogenating an alkane over a catalyst: C₂H₆ → C₂H₄ + H₂; (3) zinc acting on a vicinal dibromoalkane: CH₂Br–CH₂Br + Zn → C₂H₄ + ZnBr₂; (4) alcoholic KOH acting on a haloalkane: C₃H₇Cl + KOH → C₃H₆ + KCl + H₂O.

Worked examples
Open-chain isomers of C₅H₁₀: pentene-1, pentene-2, 2-methylbutene-1, 3-methylbutene-1, 2-methylbutene-2 (5, not counting cis/trans). Pentene-2 has cis- and trans- forms.
From 92 g of ethanol (2 mol), C₂H₅OH → C₂H₄ + H₂O gives 2 mol, i.e. 56 g. If zinc acts on 94 g of 1,2-dibromoethane (M = 188, 0.5 mol), CH₂Br–CH₂Br + Zn → C₂H₄ + ZnBr₂ gives 0.5 mol, i.e. 14 g, of ethylene.
Class activity

Build cis- and trans-butene-2 with two colours of plasticine and two parallel sticks, then try to “rotate” one carbon — the sticks block it. Use this to explain the lack of rotation.

Practice
1
What kind of isomers are butene-1 and butene-2?
2
How many grams of ethylene form from 92 g of ethanol (M(C₂H₅OH) = 46, M(C₂H₄) = 28)?
3
Propanol-1 (M = 60) is dehydrated to propene (M = 42). How many grams of propene can be obtained from 120 g of propanol-1?
4
Propene has no cis-/trans- isomers. Explain why.