☰ خطة العام · الرياضيات البحتة (بالإنجليزية)

The vector product, areas and the scalar triple product

الأسبوع 11 · الضرب الاتجاهي: التعريف والإحداثيات والتوازي والمساحات والضرب الثلاثي القياسي والحجوم · 3 دروس
3

Areas from the vector product, and the scalar triple product and the volume of a parallelepiped

Pure Mathematics Sec 3 Term 1, Unit 3, Lesson 3
GoalFind areas of parallelograms and triangles from the vector product, and find volumes with the scalar triple product.
New words
area of a parallelogram · ‖A × B‖ for the parallelogram with sides A and B; the triangle on A and B has half of itscalar triple product · A · (B × C), a number; it equals a 3 by 3 determinant with rows A, B, Cparallelepiped · a solid with six faces that are parallelograms; a box is a special case
Explanation

Take the parallelogram with adjacent sides A and B. Its base is ‖A‖ and its height is ‖B‖ sin θ, so its area is ‖A‖‖B‖ sin θ = ‖A × B‖. The triangle on the same two sides is half of it: area = ½‖A × B‖. For a triangle PQR use A = PQ and B = PR. Now take three vectors A, B, C from one point. The scalar triple product (in Arabic الضرب الثلاثي القياسي) is A · (B × C): first do B × C, which gives a vector, then take its dot product with A, which gives a number. No brackets are needed in A · B × C because B × C must be done first. It is the 3 by 3 determinant with the three vectors as rows. Cyclic order does not change it: A · (B × C) = B · (C × A) = C · (A × B), but swapping two vectors changes the sign. Geometry: the three vectors are three edges of a parallelepiped (in Arabic متوازي السطوح), and its volume is |A · (B × C)|: the base area ‖B × C‖ times the height, which is the component of A along the direction of B × C. If the three vectors lie in one plane the solid is flat, so the triple product is 0, and this is the test for coplanar vectors. The scalar triple product is used in statics and in design, where volumes and moments are needed.

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Worked examples
A parallelogram has sides A = (3, 2, 2) and B = (1, −2, 2). A × B = (2 × 2 − 2 × (−2), −(3 × 2 − 2 × 1), 3 × (−2) − 2 × 1) = (8, −4, −8). Its size is √(64 + 16 + 64) = 12, so the area is 12 square units and the triangle on the same sides has area 6.
Triangle with vertices P(1, 2, 0), Q(3, 1, 4), R(0, 5, 2). PQ = (2, −1, 4) and PR = (−1, 3, 2). PQ × PR = (−1 × 2 − 4 × 3, −(2 × 2 − 4 × (−1)), 2 × 3 − (−1)(−1)) = (−14, −8, 5). Its size is √(196 + 64 + 25) = √285, so the area is √285/2 ≈ 8.44 square units.
Let A = (1, 0, 2), B = (3, 1, −1), C = (2, 2, 1). The determinant is 1 × (1 × 1 − (−1) × 2) − 0 + 2 × (3 × 2 − 1 × 2) = 3 + 8 = 11. So A · (B × C) = 11 and the volume of the parallelepiped is 11 cubic units. In the cyclic order C · (A × B) is also 11.
Are (1, 2, 3), (2, −1, 1) and (4, 3, 7) in one plane? The determinant is 1 × (−7 − 3) − 2 × (14 − 4) + 3 × (6 + 4) = −10 − 20 + 30 = 0. Yes: they are coplanar (the third is twice the first plus the second).
Class activity

Volume of a brick. A brick of 2 by 3 by 5 units has edges along i, j, k: A = 2i, B = 3j, C = 5k. Check with the determinant that A · (B × C) = 30, which is the length times the width times the height. Then slant the top by changing C to (1, 1, 5): does the volume change? (It does not: the base and the height are the same.)

Practice
1
Find the area of the parallelogram with sides (2, 0, 1) and (0, 3, 1).
2
A triangle has sides AB = (1, 1, 2) and AC = (0, 3, −1). Find its area.
3
Find the volume of the parallelepiped with edges (1, 1, 0), (0, 2, 1) and (3, 0, 1).
4
For which k are (1, 2, 1), (2, k, 3) and (0, 1, −1) coplanar?
5
Show that A · (B × C) changes sign when B and C are swapped, using A = (1, 0, 0), B = (0, 1, 0), C = (0, 0, 1).