☰ خطة العام · الرياضيات البحتة (بالإنجليزية)

Lines and planes meeting, angles between planes, and distances

الأسبوع 14 · تقاطع مستقيم ومستوى والزاوية بين مستويين وتوازي المستويات وتعامدها وخط تقاطع مستويين والبعد بين نقطة ومستوى وبين مستويين متوازيين ومعادلة المستوى بدلالة الأجزاء المقطوعة · 3 دروس
1

Where a line meets a plane, the angle between two planes, and parallel and perpendicular planes

Pure Mathematics Sec 3 Term 1, Unit 4, Lesson 2
GoalFind where a line meets a plane, the angle between two planes, and whether two planes are parallel or perpendicular.
New words
angle between two planes · the acute (or right) angle between their normal vectorsparallel planes · planes whose normal vectors are proportional, n₁ = kn₂perpendicular planes · planes whose normal vectors have n₁ · n₂ = 0
Explanation

Where does the line r = A + t d meet the plane ax + by + cz = k? A point of the line is (x, y, z) = A + t d. Put it into the equation of the plane: the result is a linear equation in t, which is (n · d)t = k − n · A, with n = (a, b, c). Three cases, as in the table. If n · d is not 0, there is one value of t and so exactly one common point: put t back to get the point. If n · d = 0 the direction of the line is perpendicular to the normal, so the line is parallel to the plane; then either the point A is not in the plane (no solution: no common point) or it is (every t works: the line lies in the plane). Next, two planes. Their angle is the angle between their normal vectors, taken acute: cos θ = |n₁ · n₂|/(‖n₁‖‖n₂‖), 0° ≤ θ ≤ 90°. The planes are parallel when the normals are proportional, n₁ = kn₂, and perpendicular when n₁ · n₂ = 0. Different parallel planes do not meet; in other cases two planes meet in a line, studied in the next lesson. Always read normal vectors from the coefficients of x, y, z, and take care with equations written in a different order.

put the general point (A + t d) into the equation of the plane: it becomes (n · d)t = constant
n · dis a point of the line in the plane?the line and the plane
not 0(not needed)meet in exactly one point: find t
0noparallel: no common point
0yesthe line lies in the plane
Worked examples
Where does r = (1, 0, 2) + t(2, 1, −1) meet x + 2y + 3z = 9? The point is (1 + 2t, t, 2 − t), so 1 + 2t + 2t + 6 − 3t = 9, that is 7 + t = 9 and t = 2. The point is (5, 2, 0). Check: 5 + 4 + 0 = 9.
The same direction d = (2, 1, −1) has n · d = 2 + 2 − 3 = 1, which is not 0, so any line with this direction meets this plane. Now take the line (0, 1, 1) + t(1, 1, −1): n · d = 1 + 2 − 3 = 0. The point (0, 1, 1) gives 0 + 2 + 3 = 5. For the plane x + 2y + 3z = 9 that is not 9, so the line is parallel to the plane and never meets it; for the plane x + 2y + 3z = 5 the line lies in the plane.
The angle between x + 2y + 2z = 3 and 3x − 4y = 5. The normals are (1, 2, 2) and (3, −4, 0), with dot product 3 − 8 = −5 and norms 3 and 5. cos θ = 5/15 = 1/3 and θ ≈ 70.5°.
Unknown constants. 3x − 6y + kz = 1 is parallel to x + my + 2z = 4 when (3, −6, k) = 3(1, m, 2): m = −2 and k = 6. And 2x − y + kz = 3 is perpendicular to 3x + 4y + 2z = 1 when 6 − 4 + 2k = 0, so k = −1.
Class activity

Folded card and a pencil. Fold a card to make a book standing on a table: the table and the page are two planes meeting along the fold. Push a pencil through the page: does it meet the table plane? Try the pencil parallel to the table: this is the case n · d = 0.

Practice
1
Find where the line r = (2, −1, 3) + t(1, 2, −2) meets the plane 3x − y + 2z = 4.
2
Show that the line (0, 0, 5) + t(1, 1, 1) is parallel to the plane x − 2y + z = 3, and say what happens for the plane x − 2y + z = 5.
3
Find the angle between the planes x − 2y + 2z = 1 and 3y − 4z = 2.
4
Find a and b so that 2x + ay − 4z = 1 is parallel to bx − 3y + 8z = 5.
5
Find k so that 2x + ky + z = 7 is perpendicular to x − 2y + 4z = 3.