☰ Contents · Algebra

The method of intervals

Lessons 9 · 1 lessons · Sh.A. Alimov, A.R. Xalmukhamedov, M.A. Mirzaakhmedov. Algebra: textbook for Grade 9 of general secondary schools. Revised 4th edition. Tashkent: “O‘qituvchi”, 2019
9

The method of intervals

Textbook: pp. 32–36
GoalSolve inequalities (factorable ones and fractions) by the method of intervals.
New words
method of intervals · intervallar usuliinterval · intervalalternation of signs · ishoralar almashinuvifractional inequality · kasr tengsizlik
Explanation

The method of intervals solves inequalities that are products or fractions. The procedure: 1) factor the expression into factors (x − a); 2) mark the zeros of the factors on the number line, which splits it into intervals; 3) in the rightmost interval every (x − a) is positive, so the expression is positive (if the leading coefficient is positive); 4) moving right to left the expression changes sign at each zero; 5) write down the intervals with the required sign. If a factor appears with an even power, such as (x − 3)², it does not change sign at its zero, but x = 3 may still be a solution of a non-strict inequality. For a fraction we mark the zeros of numerator and denominator; zeros of the denominator are never solutions, because the fraction is not defined there.

Worked examples
(x − 3)²(x + 1) > 0: (x − 3)² ≥ 0 and equals zero at x = 3, so x ≠ 3 and x + 1 > 0, i.e. x > −1. Answer: −1 < x < 3 or x > 3.
(x − 1)(x + 2) : (x − 3) ≤ 0: zeros −2, 1, 3. Signs: x > 3: +; 1 < x < 3: −; −2 < x < 1: +; x < −2: −. Zeros of the numerator are included, the denominator's is not. Answer: x ≤ −2 or 1 ≤ x < 3.
Class activity

“Chain of signs”: a number line is drawn on the board; students take turns marking one zero and say whether the sign changes there (watch for even powers!).

Practice
1
Solve (x + 2)(x − 1)(x − 4) < 0.
2
Solve x(x − 3)(x + 5) ≥ 0.
3
Solve (x − 4) : (x + 1) > 0.
4
Why does the factor (x − 2)² not change sign at x = 2?