☰ Contents · Algebra

Quadratic inequality and its solution

Lessons 7 · 1 lessons · Sh.A. Alimov, A.R. Xalmukhamedov, M.A. Mirzaakhmedov. Algebra: textbook for Grade 9 of general secondary schools. Revised 4th edition. Tashkent: “O‘qituvchi”, 2019
7

Quadratic inequality and its solution

Textbook: pp. 24–27
GoalKnow what a quadratic inequality is and solve it by factoring the quadratic trinomial.
New words
quadratic inequality · kvadrat tengsizliksolution of an inequality · tengsizlikning yechimiquadratic trinomial · kvadrat uchhadsystem of inequalities · tengsizliklar sistemasi
Explanation

An inequality with a quadratic function on the left and zero on the right is called a quadratic inequality: ax² + bx + c > 0 (or <, ≥, ≤), where a ≠ 0. A solution is any value of x that turns it into a true numerical inequality; to solve it means to find all solutions or to show there are none. If the roots of ax² + bx + c = 0 are x₁ < x₂, the trinomial factors as a(x − x₁)(x − x₂). A product of two factors is positive when they have the same sign and negative when their signs differ, so the inequality leads to two systems of first-degree inequalities. If a < 0 we first multiply both sides by −1 and reverse the inequality sign. The result: (x − x₁)(x − x₂) > 0 gives x < x₁ or x > x₂, while (x − x₁)(x − x₂) < 0 gives x₁ < x < x₂.

Worked examples
x² − 4x − 5 < 0: the roots are −1 and 5, (x + 1)(x − 5) < 0. The product is negative, so the factors have different signs: x + 1 > 0 and x − 5 < 0 give −1 < x < 5; the system x + 1 < 0 and x − 5 > 0 has no solution. Answer: −1 < x < 5.
−2x² + x + 3 ≥ 0: multiply by −1: 2x² − x − 3 ≤ 0. D = 1 + 24 = 25, x = (1 ± 5) : 4, so x₁ = −1, x₂ = 3/2. 2(x + 1)(x − 3/2) ≤ 0, hence −1 ≤ x ≤ 3/2.
Class activity

“Sign race”: split the class into two teams. The teacher calls out an inequality (x − a)(x − b) > 0 or < 0; the teams take turns writing the signs of the factors and the solution on the board.

Practice
1
Which of x² − 9 > 0, 2x + 1 < 0, 3x² − x − 4 ≤ 0 are quadratic inequalities?
2
Solve (x − 3)(x + 2) < 0.
3
Solve x² − 6x + 8 ≥ 0.
4
Why does the sign reverse when we multiply an inequality by −1?