A body thrown vertically upward

For a body thrown upward, ignoring air resistance, only the force of gravity acts, so the acceleration always points downward and equals g (we take g = 10 m/s² in problems). While rising the body slows down: υ = υ₀ − gt, with height h = υ₀t − gt²/2. At the top the velocity is zero, so the time of ascent is t = υ₀/g; putting this into the height formula gives the maximum height h = υ₀²/(2g). On the way down it speeds up from rest and returns to the launch point with a speed equal to the initial one; the whole flight lasts 2υ₀/g. Rising and falling are symmetric motions.