☰ Contents · Physics

Force of gravity and weight of a body

Lessons 27–28 · 2 lessons · P.Q. Habibullayev, A. Boydedayev, A.D. Bahromov, S.O. Burxonov. Physics Grade 7, revised and enlarged 4th edition. “O‘zbekiston milliy ensiklopediyasi” State Scientific Publishing House, Tashkent, 2017
27

Force of gravity

Textbook: pp. 100–101
GoalKnow the force of gravity F = mg and how g varies over the Earth.
New words
force of gravity · og‘irlik kuchifree-fall acceleration · erkin tushish tezlanishimass of the Earth · Yerning massasiEarth’s radius · Yer radiusi
Explanation

The Earth attracts a body near its surface; this force is the force of gravity: F = mg, where g is the free-fall acceleration. From the law of universal gravitation g = GM/R², with M the Earth’s mass and R its radius (about 6400 km). The calculation gives g ≈ 9.8 m/s²; in problems g = 10 m/s² is often used. g is slightly larger at the poles (9.83 m/s²) and smaller at the equator (9.78 m/s²), because the Earth is flattened at the poles and rotates. g decreases with height above the surface. The force of gravity is proportional to the body’s mass, directed toward the Earth’s centre (vertically down) and applied at the body’s centre of mass.

Worked examples
m = 5 kg (g = 10 m/s²): F = 5 · 10 = 50 N.
If F = 200 N, then m = F/g = 200 : 10 = 20 kg.
Class activity

“From mass to force”: the class converts the masses of some everyday items (book 0.5 kg, bag 4 kg) into forces of gravity. Safety: adults lift heavy items.

Practice
1
What is the formula for the force of gravity?
2
Force of gravity on m = 12 kg (g = 10 m/s²), N?
3
If the force of gravity is 450 N, the mass (g = 10 m/s²), kg?
4
Why is g smaller at the equator than at the poles?