Lessons 28 · 1 lessons · S. Masharipov, A. Mutalibov, E. Murodov, H. Islomova. General chemistry, Grade 11, 1st edition. G‘afur G‘ulom Publishing and Printing House, Tashkent, 2018
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Balancing redox reactions by the half-reaction method
Textbook: pp. 127–132
GoalBalance redox reactions by the half-reaction method in acidic and alkaline media.
In the half-reaction method separate half-reactions are written for the oxidising and the reducing agent; they involve particles that really exist in the solution (MnO₄⁻, SO₃²⁻, Cr₂O₇²⁻, H⁺, OH⁻, H₂O), not formal ions such as N⁵⁺. The order: 1) balance the atoms of the changing element; 2) balance oxygen; 3) balance hydrogen; 4) balance charge with electrons; 5) equalise the numbers of electrons and add the half-reactions; 6) cancel identical particles on both sides; 7) convert to the molecular equation. In acidic medium add one H₂O for each missing O to the side lacking oxygen, then H⁺ to the side lacking hydrogen. In alkaline medium add 2OH⁻ for each missing O to the side lacking oxygen and 1 H₂O to the other side. At the end check that atoms and total charge are equal on both sides.
Paper exercise: cover the two examples and balance them again from the list of steps; then check atoms and charge in each equation and mark each other’s work.
Practice
1
Balance the half-reaction Cr₂O₇²⁻ → Cr³⁺ in acidic medium and find the sum of all its coefficients.
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2
Write the half-reaction SO₃²⁻ → SO₄²⁻ in alkaline medium.
SO₃²⁻ + 2OH⁻ − 2e⁻ → SO₄²⁻ + H₂O
3
The oxidising agent accepts 5 e⁻ and the reducing agent gives 2 e⁻. What are the multipliers and how many electrons are transferred in total?
Oxidising agent ×2, reducing agent ×5; 10 e⁻ in total
4
Why is NO₃⁻ written in a half-reaction rather than N⁵⁺?
NO₃⁻ really exists in solution; N⁵⁺ is only a formal oxidation state.