☰ Contents · Physics

Photometry and illuminance

Lessons 30–31 · 2 lessons · N. Sh. Turdiyev, K. A. Tursunmetov, A. G. Ganiyev, K. T. Suyarov, J. E. Usarov, A. K. Avliyoqulov. Physics Grade 11, 1st edition. Niso Poligraf Publishing House, Tashkent, 2018
30

Luminous flux. Luminous intensity. The law of illuminance

Textbook: pp. 110–114
GoalKnow the photometric quantities (luminous flux, luminous intensity, illuminance, luminance) and their units, and apply the law of illuminance E = I·cosφ/R².
New words
luminous flux (lm) · yorug‘lik oqimi (lm)luminous intensity (cd) · yorug‘lik kuchi (cd)illuminance (lx) · yoritilganlik (lx)solid angle (sr) · fazoviy burchak (sr)
Explanation

Photometry measures the effect of light on the eye. Luminous flux Φ (unit: lumen, lm) is the radiant power of the source as sensed by the eye. Luminous intensity I is the flux of a source per unit solid angle in a given direction: I = Φ/Ω; its unit, the candela (cd), is one of the SI base units (current definition: the luminous intensity in a direction in which monochromatic radiation of frequency 540·10¹² Hz has a radiant intensity of 1/683 W/sr; this is a wavelength of ≈ 555 nm, the green light to which the eye is most sensitive). Solid angle Ω = S₀/R² (steradian, sr); the whole space is 4π sr, so a point source's total flux is Φ = 4π·I. Illuminance E = Φ/S (unit: lux, 1 lx = 1 lm/m²). At distance R from a point source, E = I/R² if the light falls perpendicular to the surface and E = I·cosφ/R² if the ray makes angle φ with the surface normal; illuminances of several sources add. Luminance B = I/S (cd/m²) is the luminous intensity per unit area of the emitting surface. Illuminance falls with distance by the inverse-square law.

Worked examples
A point source has luminous intensity 60 cd: total flux Φ = 4πI = 4·3.14·60 ≈ 754 lm. A lamp (I = 80 cd) hangs 2 m above a table: directly below it E = I/R² = 80/4 = 20 lx.
For the same lamp at a point where the ray makes φ = 60° with the normal (take R = 2 m): E = I·cosφ/R² = 80·0.5/4 = 10 lx. For 300 lx at 1 m the required I = E·R² = 300 cd.
Class activity

At home: compare a desk lamp measured with a phone light-meter app (or luxmeter) from 0.5 m and 1 m to check how E depends on distance (about a 4-fold difference expected). Do not stare at a bright lamp for long and do not touch lamps (they can be hot).

Practice
1
What are the units of luminous intensity and illuminance?
2
I = 200 cd and R = 2 m. What is the illuminance in lx (light perpendicular)?
3
Solid angle 2 sr and R = 3 m. What is the area S₀ cut from the sphere in m²?
4
Why does the illuminance fall 4 times when the distance doubles?