☰ Contents · Physics

Interference and diffraction of light

Lessons 25 · 1 lessons · N. Sh. Turdiyev, K. A. Tursunmetov, A. G. Ganiyev, K. T. Suyarov, J. E. Usarov, A. K. Avliyoqulov. Physics Grade 11, 1st edition. Niso Poligraf Publishing House, Tashkent, 2018
25

Interference and diffraction of light

Textbook: pp. 91–95
GoalExplain and calculate light interference (conditions for maxima and minima, Young's experiment, thin films, Newton's rings) and diffraction (the grating formula d·sinφ = nλ).
New words
interference · interferensiyacoherent waves · kogerent to‘lqinlarpath difference · yo‘l farqidiffraction grating · difraksion panjara
Explanation

When waves of equal frequency and constant phase difference (coherent waves) meet, they strengthen each other at some points and weaken at others: this is interference. If the path difference Δd = d₂ – d₁ equals an even number of half-waves, there is a maximum: Δd = 2k·λ/2 = kλ; if it equals an odd number there is a minimum: Δd = (2k + 1)·λ/2 (k = 0, 1, 2, …). Two separate lamps are not coherent, because atoms emit light independently and at random; so the light of one source is artificially split in two: in Young's experiment (1801) by two narrow slits, in a thin film (a soap bubble, an oil layer) by reflection from the upper and lower surfaces, in Newton's rings by reflection from the air layer between a lens and a plate. For slit separation d and screen distance L the distance between neighbouring bright fringes is Δy = λL/d. Diffraction is the bending of a wave around an obstacle or the edge of a slit, clearly noticeable when the obstacle's size is comparable to the wavelength. For a diffraction grating of period d the bright maxima are seen when d·sinφ = nλ (n = 0, 1, 2, …); in white light the centre is white and spectra appear on the sides. These phenomena confirm the wave nature of light.

Worked examples
Young's experiment: λ = 600 nm, slit separation d = 0.3 mm, screen L = 1.5 m. Δy = λL/d = 6·10⁻⁷·1.5/(3·10⁻⁴) = 3·10⁻³ m = 3 mm. The second bright fringe is at 2Δy = 6 mm from the centre.
A grating has 400 lines/mm: d = 1 mm/400 = 2.5 μm; λ = 500 nm. sinφ = nλ/d = n/5; n = 1: φ ≈ 11.5°; n = 2: sinφ = 0.4, φ ≈ 23.6°. Since sinφ ≤ 1, n < 5, so at most the 4th-order maximum is seen.
Class activity

A safe experiment: make a soap film on a wire ring and watch coloured fringes in white lamp light and how they move downward. See the spectra from a lamp or phone flashlight reflected from the surface of a compact disc (CD). Do not look at the Sun and never point a laser at anyone's eyes.

Practice
1
What is the condition for an interference maximum?
2
λ = 0.6 μm. If the path difference is 0.9 μm, what is observed at the point?
3
Grating period 4 μm, λ = 500 nm; what is the order n of the maximum at φ = 30°? (sin30° = 1/2)
4
Why do two identical lamps not give an interference pattern?