☰ SAT · Math

Linear equations in one variable

SAT Math · Algebra · Week 1 of the 12-week plan
1

Linear equations in one variable

College Board skill: Linear equations in one variable
GoalSolve any linear equation in one step-by-step way, tell when it has one, no or infinitely many solutions, and turn a word problem into an equation.
On the test

Algebra is about 35% of SAT Math (13–15 of 44 questions). Linear equations in one variable appear in both modules, as multiple choice and as typed answers, often inside a short real-life story.

Key words
coefficient · the number in front of a variable: in 7x, it is 7constant · a number on its own, with no variablesolution · a value of x that makes both sides equalidentity · an equation that is true for every x
Explanation

Keep the balance

An equation is a balance: whatever you do to one side, do to the other. Work in the same order every time. 1) Remove brackets by distributing. 2) Clear fractions or decimals by multiplying every term by the same number. 3) Collect the x-terms on one side and the plain numbers on the other. 4) Divide by the coefficient of x. 5) Check by putting your answer back into the original equation.

One, none or infinitely many solutions

After simplifying, every linear equation looks like ax + b = cx + d. If the x-coefficients are different (a ≠ c), there is exactly one solution. If the x-coefficients are equal but the constants are different (a = c, b ≠ d), the x-terms cancel and you are left with something false, such as 3 = 5: there is no solution. If both sides are exactly the same (a = c and b = d), the equation is an identity: every number is a solution. The SAT likes to ask for the constant that makes an equation have no solution or infinitely many.

After simplifyingExampleSolutions
a ≠ c2x + 3 = 5x − 9exactly one (x = 4)
a = c, b ≠ d2x + 3 = 2x − 1none (3 = −1 is false)
a = c, b = d2x + 3 = 2x + 3infinitely many

See it as two lines

Each side of an equation can be drawn as a line: y = left side and y = right side. The solution is the x-coordinate of the point where the lines cross. Lines with the same slope never cross unless they are the same line, which is why equal x-coefficients mean no solution or infinitely many.

xy−4−3−2−11234−6−4−22468100y = 2x + 3y = 2x − 1

Answer the question that was asked

Many SAT questions do not ask for x. They ask for 2x + 3, or x − 1, or 6x. Before solving, look at the last line of the question. Sometimes you can get the asked expression directly: if 6x + 9 = 24, divide both sides by 3 to get 2x + 3 = 8 without ever finding x.

From words to an equation

Name the unknown with a letter and say what it means, with units. Write each amount in the story as an expression in that letter. Then find the sentence that says two amounts are equal (“costs the same”, “the total was”, “is twice as long as”) and turn it into the equation.

Worked examples
Example 1.
Solve x/3 + (x + 2)/4 = 4.
  1. The denominators are 3 and 4, so multiply every term by 12.
  2. 4x + 3(x + 2) = 48
  3. 4x + 3x + 6 = 48
  4. 7x = 42, so x = 6.
  5. Check: 6/3 + 8/4 = 2 + 2 = 4 ✓
Example 2.
In the equation 3(2x − 5) + kx = 4x + 7 − x, k is a constant. For what value of k does the equation have no solution?
  1. Simplify the left side: 6x − 15 + kx = (6 + k)x − 15.
  2. Simplify the right side: 3x + 7.
  3. No solution means equal x-coefficients and different constants.
  4. 6 + k = 3, so k = −3. The constants −15 and 7 are different ✓
Example 3.
If 6x + 9 = 24, what is the value of 2x + 3?
  1. Notice that 6x + 9 = 3(2x + 3).
  2. So 3(2x + 3) = 24.
  3. Divide both sides by 3: 2x + 3 = 8.
Trap: Finding x = 2.5 and stopping there gives a wrong answer that is often one of the choices.
Example 4.
Gym A charges a $40 joining fee and $25 per month. Gym B has no joining fee and charges $33 per month. After how many months will the total cost be the same at both gyms?
monthscost, $1234567840801201602002402800Gym AGym B(5, 165)
  1. Let m be the number of months.
  2. Gym A: 40 + 25m. Gym B: 33m.
  3. 40 + 25m = 33m
  4. 40 = 8m, so m = 5.
  5. Check: 40 + 125 = 165 and 33 × 5 = 165 ✓
Common traps
  • Losing a minus sign when distributing−2(x − 3) = −2x + 6, not −2x − 6. Multiply the minus by every term inside the brackets.
  • Clearing fractions in only some termsWhen you multiply by 12, multiply every term, including the ones without a fraction: x/3 + 1 = 5 becomes 4x + 12 = 60.
  • Answering x when the question asks for something elseUnderline what is asked (2x + 3, x − 1, the cost…) and read it again before choosing.
  • Mixing up “no solution” and “infinitely many”Same x-coefficient + different constants → none. Everything the same → infinitely many.
  • Typing an answer in the wrong formIn typed-answer questions enter 7/2 or 3.5, never 3 1/2. Up to 5 characters for a positive answer, 6 for a negative one. No $ or % signs and no units.
The Desmos way

Desmos is built into every Math question. Type the left side as y = … and the right side as y = … on two lines. The x-coordinate of the point where the two lines cross is the solution; click the crossing point to see its coordinates. You can also type the equation exactly as written: Desmos then draws a vertical line at the solution.

  1. Type y = x/3 + (x + 2)/4
  2. Type y = 4
  3. Click the crossing point: it is (6, 4), so x = 6
  4. For “no solution” questions: parallel lines mean no solution; one line exactly on top of the other means infinitely many

Use Desmos to check an answer or when the numbers are ugly (decimals, large fractions). For simple equations, solving by hand is usually faster.

Open Desmos ↗
Quick check
1
Solve 7x − 4 = 3x + 20.
2
Solve 2(3x + 1) − (x − 4) = 31.
3
How many solutions does 4(x − 2) + 3 = 4x − 5 have?
4
If 10x − 15 = 35, what is the value of 2x − 3?
Practice set: 10 SAT-style questionsEasy → hard, with typed answers like the real test. Your score is saved in your cabinet.
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