Week 1 · Complex numbers: the imaginary unit i, powers of i, the form a + bi, equality, operations, conjugates and division · 3 lessons
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The complex number a + bi: real and imaginary parts, solving x² = −k and equality of two complex numbers
Mathematics Sec 1 Term 1, Unit 1, Lesson 1
GoalWrite numbers in the form a + bi, solve equations such as x² = −k and use the equality of two complex numbers.
New words
complex number · a number a + bi where a and b are realreal part / imaginary part · a is the real part and b is the imaginary part (b, not bi)pure imaginary · a complex number with a = 0 and b ≠ 0
Explanation
A complex number is any number of the form a + bi, where a and b are real numbers. The number a is its real part and b is its imaginary part (note that it is b, not bi). If b = 0 the number is just the real number a; if a = 0 and b ≠ 0 it is pure imaginary. So every real number is also complex: the sets N, Z, Q and R all sit inside the set of complex numbers. Complex numbers let us solve x² = −k for k > 0: x = ±√k × i. For example x² = −16 gives x = ±4i, and you can check (4i)² = 16 × (−1) = −16. Two complex numbers are equal exactly when their real parts are equal and their imaginary parts are equal: a + bi = c + di means a = c and b = d. This turns one complex equation into two ordinary equations, which is how we find unknown x and y.
Find x and y if (x + 2y) + (3x − y)i = 7 + 7i. Equal real parts: x + 2y = 7. Equal imaginary parts: 3x − y = 7. From the second, y = 3x − 7. Put it in the first: x + 6x − 14 = 7, so x = 3 and y = 2. Check: 3 + 4 = 7 and 9 − 2 = 7 ✓.
Class activity
Real or imaginary? Write five complex numbers of your own on paper, one with b = 0, one with a = 0 and three others. Under each give its real part and its imaginary part.
Practice
1
Write the real and imaginary parts of 6 − 4i and of 9i.
6 − 4i: real part 6, imaginary part −4. 9i: real part 0, imaginary part 9.
2
Solve 2x² + 75 = 25.
2x² = −50, x² = −25, x = ±5i.
3
Solve 3x² + 27 = 0.
x² = −9, so x = ±3i.
4
Find x and y if (2x − y) + (x + y)i = 4 + 5i.
2x − y = 4 and x + y = 5. Adding: 3x = 9, so x = 3 and y = 2. Check: 6 − 2 = 4 ✓.
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Is 5i a real number? What is its real part?
No, it is pure imaginary. Its real part is 0 and its imaginary part is 5.