Products, quotients and powers in trigonometric form, and the exponential form
Week 5 · Products, quotients and powers in trigonometric form, and the exponential (Euler) form of a complex number · 3 lessons
1
Multiplying and dividing in trigonometric form: moduli multiply, amplitudes add
Pure Mathematics Sec 3 Term 1, Unit 2, Lesson 1
GoalMultiply and divide complex numbers in trigonometric form: moduli multiply or divide, amplitudes add or subtract.
New words
product rule · z1·z2 = r1r2 (cos(θ1+θ2) + i sin(θ1+θ2))quotient rule · z1 ÷ z2 = (r1/r2)(cos(θ1−θ2) + i sin(θ1−θ2))
Explanation
Take z1 = r1(cos θ1 + i sin θ1) and z2 = r2(cos θ2 + i sin θ2) and multiply, remembering i² = −1: z1z2 = r1r2[(cos θ1 cos θ2 − sin θ1 sin θ2) + i(sin θ1 cos θ2 + cos θ1 sin θ2)]. Recall the sum formulas from Secondary 2: cos(A + B) = cos A cos B − sin A sin B and sin(A + B) = sin A cos B + cos A sin B. The brackets are exactly these, so z1z2 = r1r2[cos(θ1 + θ2) + i sin(θ1 + θ2)]: moduli multiply, amplitudes add. Multiplying z by (1/r)(cos(−θ) + i sin(−θ)) gives modulus r × (1/r) = 1 and amplitude θ − θ = 0, that is 1, so 1/z = (1/r)(cos(−θ) + i sin(−θ)), and the quotient rule follows: z1 ÷ z2 = (r1/r2)[cos(θ1 − θ2) + i sin(θ1 − θ2)]: moduli divide, amplitudes subtract. A warning: the sum or difference of two principal amplitudes can leave ]−π, π]. Add or subtract 2π to bring the answer back. Pictures help: multiplying by z2 stretches the plane by r2 and turns it by θ2; so multiplying by i (r = 1, θ = π/2) is a quarter turn anticlockwise.
Worked examples
Multiply 2(cos π/6 + i sin π/6) by 5(cos π/3 + i sin π/3). The moduli give 2 × 5 = 10 and the amplitudes π/6 + π/3 = π/2. So the product is 10(cos π/2 + i sin π/2) = 10i.
Divide 6(cos 5π/6 + i sin 5π/6) by 2(cos π/6 + i sin π/6). Moduli: 6 ÷ 2 = 3. Amplitudes: 5π/6 − π/6 = 2π/3. The quotient is 3(cos 2π/3 + i sin 2π/3) = 3(−1/2 + (√3/2) i) = −3/2 + (3√3/2) i.
Multiply 3(cos 2π/3 + i sin 2π/3) by 2(cos 3π/4 + i sin 3π/4). The amplitudes add up to 2π/3 + 3π/4 = 8π/12 + 9π/12 = 17π/12, which is more than π. Subtract 2π = 24π/12: the principal amplitude is −7π/12. The product is 6(cos(−7π/12) + i sin(−7π/12)).
Read from the diagram: |z1| = 2 at 50° and |z2| = 3 at −110°. Then z1z2 has modulus 6 and amplitude 50° + (−110°) = −60°. And z1 ÷ z2 has modulus 2/3 and amplitude 50° − (−110°) = 160°, which is inside ]−180°, 180°].
Class activity
Quarter turn. Take z = 2(cos π/3 + i sin π/3) = 1 + √3 i and multiply it by i in two ways: with the polar rule and with ordinary algebra. Do the answers agree?
Practice
1
Multiply 4(cos π/5 + i sin π/5) by 3(cos 3π/5 + i sin 3π/5).
12(cos 4π/5 + i sin 4π/5), since π/5 + 3π/5 = 4π/5.
2
Divide 10(cos 7π/12 + i sin 7π/12) by 5(cos π/12 + i sin π/12).
Modulus 2, amplitude 7π/12 − π/12 = π/2, so 2(cos π/2 + i sin π/2) = 2i.
3
Multiply 5(cos 5π/6 + i sin 5π/6) by 2(cos 3π/4 + i sin 3π/4) and give the principal amplitude.
5π/6 + 3π/4 = 10π/12 + 9π/12 = 19π/12 > π, so subtract 2π: −5π/12. The product is 10(cos(−5π/12) + i sin(−5π/12)).
4
Divide 4(cos(−2π/3) + i sin(−2π/3)) by 2(cos π/2 + i sin π/2).
−2π/3 − π/2 = −4π/6 − 3π/6 = −7π/6, which is below −π. Add 2π: 5π/6. The quotient is 2(cos 5π/6 + i sin 5π/6).
5
For z = 2(cos π/3 + i sin π/3) find i·z in trigonometric form and as x + yi.
i = 1(cos π/2 + i sin π/2), so i·z = 2(cos 5π/6 + i sin 5π/6) = −√3 + i. Check: z = 1 + √3 i, and i(1 + √3 i) = i − √3.