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Review: divisibility and fractions with different denominators

Lessons 52–53 · 2 lessons · M.A. Mirzaahmedov, A.A. Rahimqoriyev, Sh.N. Ismailov, M.A. To‘xtaxodjayeva. Mathematics Grade 6, 2nd edition. O‘qituvchi NMIU, Tashkent, 2017
52

Final review: divisibility of numbers

Textbook, p. 227
GoalReview divisibility tests, primes, GCD and LCM.
New words
divisibility test · bo‘linish belgisiprime factor · tub ko‘paytuvchiGCD · EKUBLCM · EKUK
Explanation

Divisibility tests: by 2 — the last digit is even; by 5 — the last digit is 0 or 5; by 10 — the last digit is 0; by 3 and 9 — the digit sum is divisible by 3 or 9 respectively. A prime number is divisible only by 1 and itself. Factoring a composite number into primes helps to find the GCD and LCM: the GCD takes the common prime factors with the smallest powers, the LCM takes all prime factors with the greatest powers. Always a · b = GCD(a, b) · LCM(a, b). If a number is divisible by both 2 and 3, it is divisible by 6, because 2 and 3 are coprime.

Worked examples
3,780: it ends in 0, so it is divisible by 2, 5 and 10; the digit sum is 3 + 7 + 8 + 0 = 18, so also by 3 and 9.
36 = 2² · 3² and 60 = 2² · 3 · 5. GCD = 2² · 3 = 12, LCM = 2² · 3² · 5 = 180. Check: 12 · 180 = 2,160 = 36 · 60.
Class activity

“Digit detective”: each group gets a four-digit number and finds, without dividing, which of 2, 3, 5, 9, 10 divide it. Another group checks by dividing. The group with the most correct answers wins.

Practice
1
Which of 4,725, 3,960, 1,234 are divisible by 9?
2
Factor 180 into primes.
3
If GCD(36, 60) = 12, find LCM(36, 60).
4
Why is a number divisible by both 2 and 3 also divisible by 6?