Configurations, oxidation states and who counts as a transition element
Week 2 Ā· Chapter 1 (B): electron configurations of the first series with the chromium and copper exceptions, oxidation states (why iron(II) oxidises easily and manganese(II) does not), the definition of a transition element, coinage metals in and zinc, cadmium and mercury out Ā· 3 lessons
3
Who counts as a transition element
Chemistry Sec 3 Term 1, Chapter 1: pp. 8ā11
GoalState the test for a transition element and apply it to copper, gold, zinc, cadmium and mercury.
New words
transition element Ā· an element whose atom, or at least one of its common ions, has a partly filled d sublevelpartly filled Ā· some but not all ten places in the sublevel taken, 1 to 9 electrons in dcoinage metals Ā· copper, silver and gold (group IB), used for coins and jewellery
Explanation
Chemists use a test, not only the position in the table: an element is a transition element if its atom, or at least one of its common ions, has a partly filled d sublevel (1 to 9 electrons in d). Apply it. Iron: the atom is 3dā¶, so yes. Scandium: the atom is 3d¹, so yes, although Sc³⺠has no d electrons; one case is enough. Copper: the atom is 3d¹ā°, which is full, but Cu²⺠is 3dā¹, partly filled, so copper counts. Gold: Au³⺠is 5dāø, so gold counts. Zinc: the atom is 3d¹Ⱐand its only common ion Zn²⺠is also 3d¹ā°, so zinc is in the d block but is not a transition element; the same holds for cadmium and mercury. Silver is a borderline case: Agāŗ is 4d¹ā°, and only the rare Ag²⺠(4dā¹) makes it a transition element, which is why courses treat it with care (extra). So the d block and the transition elements are nearly, but not exactly, the same set.
Element
Atomās d electrons
Common ion
Transition element?
Fe
3dā¶
Fe²⺠3dā¶
yes
Cu
3d¹ā°
Cu²⺠3dā¹
yes
Zn
3d¹ā°
Zn²⺠3d¹ā°
no
Sc
3d¹
Sc³⺠none
yes
Worked examples
Cadmium (Z = 48) is [Kr] 4d¹Ⱐ5s² and forms only Cd²āŗ, which is 4d¹ā°. The atom has a full d sublevel and so does the ion, so cadmium is not a transition element, like zinc above it in the same column.
Particle
d electrons
Partly filled?
Au atom
5d¹ā°
no
Au³āŗ
5dāø
yes
Gold is [Xe] 4f¹ⓠ5d¹Ⱐ6s¹. The atomās 5d is full, so look at the ions: Au³⺠is 5dāø, partly filled. Gold passes the test, which is why it is classed with copper as a transition element.
Titanium has Z = 22. The atom is [Ar] 3d² 4s², partly filled, so the test is passed at once. It does not matter that Tiā“āŗ is [Ar] with no d electrons: the definition asks for the atom or at least one ion.
Class activity
A sorting game on cards. Write on twelve cards: Sc, Ti, Mn, Fe, Ni, Cu, Zn, Ca, Ga, Cd, Au, Hg. On the back write the d electrons of the atom and of the common ion (use the lesson, a periodic table and the rules of the week). Shuffle the cards, deal them out and sort them into two piles: transition elements and not. Then stack coins as electrons in five boxes to show Cu and Cu²⺠and check that one of the two is partly filled.
Practice
1
Mercury is [Xe] 4f¹ⓠ5d¹Ⱐ6s² and forms Hg²⺠(5d¹ā°). Is it a transition element?
No. Its atom and its common ion both have a full 5d sublevel, so neither is partly filled.
2
Why is calcium not a transition element, although it comes just before the d block?
Calcium is [Ar] 4s². It has no d electrons in the atom, and Ca²⺠is [Ar]. Its last electrons go into s, so it belongs to the s block.
3
Nickel forms Ni²āŗ. Write the d configuration of the ion and decide whether it supports nickel as a transition element.
Ni²⺠is 3dāø, partly filled, so it supports the answer yes (the atom, 3dāø 4s², already does).
4
Which ion makes copper a transition element, Cuāŗ or Cu²āŗ, and why?
Cu²⺠(3dā¹): partly filled. Cuāŗ is 3d¹ā°, which is full.