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Chemical equations and conservation of mass

الأسبوع 8 · الدرس الثاني «المعادلات الكيميائية»: المعادلة الرمزية وقانون بقاء الكتلة ووزن المعادلات · 3 دروس
3

Balancing equations step by step

Science Prep 2 Term 1, Unit 2: pp. 49–56
GoalBalance a simple equation step by step by changing coefficients only.
New words
balanced equation · an equation with the same number of atoms of each element on both sidescoefficient · a number written in front of a formulasubscript · a small number inside a formula that shows how many atoms are joined
Explanation

To balance an equation, follow five steps. One: write the correct formulas. Two: count the atoms of each element on both sides. Three: change a coefficient, a number in front of a formula, to make one element equal. Four: recount all the elements. Five: check that the numbers are the simplest whole numbers. The golden rule is: change only coefficients, never the small numbers inside formulas, called subscripts. Changing a subscript changes the substance: H₂O₂ is hydrogen peroxide, not water. Do not write a coefficient of 1. Let us balance hydrogen with oxygen: H₂ + O₂ → H₂O. Left: 2 H, 2 O. Right: 2 H, 1 O. Put 2 in front of H₂O: 2 H₂O gives 4 H and 2 O. Now hydrogen needs a 2 too: 2H₂ + O₂ → 2H₂O. Left 4 H, 2 O; right 4 H, 2 O. Balanced. Remember that only the atoms must match, not the molecules: this equation has three molecules on the left and two on the right.

ElementLeft: 2H₂ + O₂Right: 2H₂O
H44
O22
Worked examples
4Na + O2→2Na2O
Balance Na + O₂ → Na₂O. Left: 1 Na, 2 O. Right: 2 Na, 1 O. Put 2 before Na₂O: 4 Na and 2 O on the right. Put 4 before Na: 4 Na on the left. Result: 4Na + O₂ → 2Na₂O. Sodium is a reactive metal, so we do this on paper only.
C2H4 + 3O2→2CO2 + 2H2O
Balance C₂H₄ + O₂ → CO₂ + H₂O (ethene, the gas that ripens fruit). Carbon: 2 on the left, so put 2 before CO₂. Hydrogen: 4 on the left, so put 2 before H₂O. Oxygen on the right is now 2 × 2 + 2 = 6, so put 3 before O₂. Result: C₂H₄ + 3O₂ → 2CO₂ + 2H₂O.
A student balances H₂ + O₂ → H₂O by writing H₂O₂ on the right. Why is this wrong? It changes the substance: H₂O₂ is hydrogen peroxide, not water.
Class activity

Balance with objects. Use paper-clips (C), beads (H) and coins (O). Build the left side of C₃H₈ + O₂ → CO₂ + H₂O. Rearrange into CO₂ and H₂O, and add more O₂ molecules as needed until all the atoms are used. Write the equation you found. It should be C₃H₈ + 5O₂ → 3CO₂ + 4H₂O. Check by counting each element.

Practice
1
Balance: Na + Cl₂ → NaCl
2
Balance: CH₄ + O₂ → CO₂ + H₂O
3
Balance: Fe + O₂ → Fe₂O₃
4
Why must we never change a subscript when balancing?