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The rest of the anions and a decision chart

الأسبوع 7 · الباب الثاني (٢): بقية الأنيونات: الثيوكبريتات والنيتريت ومجموعة حمض الكبريتيك المركز (الكلوريد والبروميد واليوديد والنيترات واختبار الحلقة البنية) ومجموعة كلوريد الباريوم (الفوسفات والكبريتات) وتدريب من إعداد Darslab على تصنيف الأنيونات · 3 دروس
2

The concentrated sulphuric acid group: chloride, bromide, iodide, nitrate

Chemistry Sec 3 Term 1, Chapter 2: pp. 35–39
GoalExplain how concentrated H₂SO₄ frees gases from chloride, bromide, iodide and nitrate, and tell the three silver halides apart.
New words
halide · a salt of chlorine, bromine or iodine, with the ion Cl⁻, Br⁻ or I⁻oxidised · changed by losing electrons; here HBr and HI give up electrons to the acidbrown-ring test · the book’s test for nitrate, using iron(II) sulphate and concentrated acid
Explanation

The second group uses concentrated sulphuric acid, which is more stable and less volatile than the acids of the anions, so it displaces them from the solid salt as gases: 2NaCl + H₂SO₄ → Na₂SO₄ + 2HCl. In a laboratory the mixture is sometimes warmed; here it is paper only. Hydrogen chloride is a colourless gas that makes white fumes with ammonia, NH₃ + HCl → NH₄Cl. Hydrogen bromide and hydrogen iodide are oxidised by the acid, HBr partly and HI quickly: 2HBr + H₂SO₄ → 2H₂O + SO₂ + Br₂ gives orange-red bromine vapour, and 2HI + H₂SO₄ → 2H₂O + SO₂ + I₂ gives violet iodine vapour. Nitrate gives nitric acid, which breaks down to brown NO₂: 2NaNO₃ + H₂SO₄ → Na₂SO₄ + 2HNO₃, then 4HNO₃ → 2H₂O + 4NO₂ + O₂. Silver nitrate confirms the three halides by colour: AgCl is white (it darkens in sunlight), AgBr pale yellow and AgI yellow; AgCl dissolves in concentrated ammonia, AgBr only slowly, AgI not at all. The book’s paper tests with starch are less clear for bromine, so the vapour colour and the silver result are the reliable evidence. Nitrate is also shown by the brown-ring test: when concentrated acid is layered under a nitrate solution mixed with fresh iron(II) sulphate, a brown ring appears where they meet. It is described here in words only.

AnionGas with concentrated H₂SO₄With AgNO₃
chloride Cl⁻HCl, white fumes with NH₃white AgCl
bromide Br⁻HBr, then orange-red Br₂pale yellow AgBr
iodide I⁻HI, then violet I₂yellow AgI
nitrate NO₃⁻brown NO₂no precipitate
Worked examples
ƒChloride
2NaCl + H₂SO₄ → Na₂SO₄ + 2HCl
Count the atoms. 2NaCl + H₂SO₄ → Na₂SO₄ + 2HCl. Left: Na 2, Cl 2, H 2, S 1, O 4. Right: Na 2, S 1, O 4, H 2, Cl 2. The equation is balanced, and the volatile HCl is the gas that leaves.
Hydrogen halideOxidised by concentrated H₂SO₄?Product
HClnonone
HBrpartlyBr₂, orange-red
HIquicklyI₂, violet
Why do bromide and iodide give coloured vapours but chloride does not? The acid oxidises HI easily, HBr partly and HCl not at all, so the ease of oxidation is I⁻ > Br⁻ > Cl⁻. In 2HI + H₂SO₄ → 2H₂O + SO₂ + I₂, iodine is set free as violet vapour. Chloride stops at HCl, which is why its gas is colourless.
Two unknown sodium salts. Salt X gives a pale yellow precipitate with silver nitrate that dissolves only slowly in concentrated ammonia: bromide, NaBr + AgNO₃ → AgBr + NaNO₃. Salt Y gives a yellow precipitate that does not dissolve in ammonia at all: iodide, NaI + AgNO₃ → AgI + NaNO₃. Colour and solubility together decide, not colour alone.
Class activity

Colour-match cards, paper only. Cut three paper swatches and colour them white, pale yellow and yellow. Write AgCl, AgBr and AgI on the backs and mix them up. Ask a friend to pick a swatch and say the halide, and then name one more fact (soluble in ammonia, slowly soluble, or not soluble) to check. Add a fourth card, the violet vapour of iodine, and a fifth, orange-red bromine. No silver nitrate, bromine or iodine is used anywhere: these are only coloured paper and the names in a table.

Practice
1
Complete and balance: KBr + H₂SO₄ → K₂SO₄ + HBr (the first step only).
2
A white precipitate darkens in sunlight and dissolves in concentrated ammonia. Which halide gave it, and what is the precipitate?
3
In 2HI + H₂SO₄ → 2H₂O + SO₂ + I₂, 0.20 mol of HI reacts. How many moles and what mass of iodine form (I = 127)?
4
Write the two equations that explain the brown gas from potassium nitrate and concentrated sulphuric acid.