☰ خطة العام · الرياضيات التطبيقية (بالإنجليزية)

Moments of any coplanar system, machines and mixed problems

الأسبوع 4 · تعميم النتيجة على أي نظام من القوى المستوية، وتطبيقات العزوم في الرافعات والقضبان المثبتة، ومسائل متنوعة · 3 دروس
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Moments in machines: a crane arm, a hinged rod, a spanner and a forearm, finding the arm with trigonometry

Applied Mathematics Sec 3 Term 1, Unit 1, Lesson 1, Part 3
GoalFind the moment of forces in machines: a hinged arm held by a tie, a pedal crank and a hinged rod, by arms from trigonometry or by components.
New words
hinge · a fixed pivot about which a rod or arm can turn; its own reaction has no moment about the hingetie, tension T · a rope or cable holding a part in place; its force acts along the ropecrank · an arm that turns about an axle, such as a bicycle pedal arm
Explanation

Machines are made of arms that turn about a hinge or an axle, and to see what a force does to one we take its moment about the hinge. Two habits make this easy. First, take moments about the hinge itself: the hinge reaction passes through it, has arm 0 and drops out. Second, find each arm with a right-angled triangle, or break the force into components along the arm and across it. A force that acts along a tie has its arm equal to the perpendicular from the hinge to the tie: for a rod of length AB hinged at A and a tie from B to a point C of the wall (AC vertical), the arm of the tension is AB × AC / BC, which is the height of the right-angled triangle on its hypotenuse. For a rod at angle θ to the horizontal and a vertical force at its end, the arm is the horizontal distance, AB cos θ. For a horizontal force at the same end, the arm is the vertical height, AB sin θ. Always say which way each force turns the arm (anticlockwise positive), then add.

TW1.2 m0.9 mABC
Worked examples
TW1.2 m0.9 mABC
A sign arm AB, 1.2 m long, is hinged to a wall at A and held horizontal by a rope from B to the point C of the wall 0.9 m above A. The rope has tension 60 N and a sign of weight 45 N hangs from B. BC = √(1.2² + 0.9²) = 1.5 m. The arm of the tension about A is 1.2 × 0.9 / 1.5 = 0.72 m, and the tension pulls B up and towards the wall: anticlockwise, +60 × 0.72 = +43.2 N·m. The weight acts down at B with arm 1.2 m: −45 × 1.2 = −54 N·m. The sum of the moments about A is −10.8 N·m: the weight wins, so the arm would turn clockwise. (Check by components: the tension is (−48, 36) N and 1.2 × 36 = 43.2.)
200 N40°17.5 cmLO
A bicycle pedal crank is 17.5 cm long and points forward and up at 40° above the horizontal. The rider pushes vertically down on the pedal with 200 N. Take the axle as O. The pedal is 0.134 m across from O (0.175 cos 40°), so the arm of the vertical force is 0.134 m. The downward push on the right of O turns clockwise: M = −200 × 0.134 ≈ −26.81 N·m. In coordinates: the pedal is at (0.134, 0.112), the force is (0, −200), and M = x Fy − y Fx = 0.134 × (−200) − 0.
25 N15 N30°80 cmAB
A light rod AB, 80 cm long, is hinged at A and rises at 30° above the horizontal. At B a force of 25 N pulls vertically down and a force of 15 N pulls horizontally towards the hinge side (to the left). B is at (0.6928, 0.4) m from A. The vertical force: arm 0.6928 m, clockwise: −17.32 N·m. The horizontal force to the left, at height 0.4 m above A, turns anticlockwise: +15 × 0.4 = +6 N·m. Total: −11.32 N·m, clockwise.
Class activity

Lean a ruler on a book as a hinged arm: hold one end at the edge of the desk as the hinge and hang a small bag (under 0.3 kg) from the other end with a loop of thread, then hold the ruler up with a second thread tied from the bag end to a point above the hinge, taken to your finger. Notice that a steeper thread needs less pull. Never hang weights over anyone’s head.

Practice
1
A rod hinged at A is 1.5 m long and makes 60° with the horizontal. A vertical force of 40 N acts downwards at its upper end. Find the moment about A (anticlockwise positive).
2
A spanner 0.4 m long has a force of 50 N at its end making 30° with the spanner. Find the size of the moment about the nut.
3
A forearm is tilted 20° above the horizontal, with the elbow at A and the hand at B 0.28 m away, and it is turned about A. The muscle pulls up at right angles to the forearm with 250 N at a point 0.05 m from A, and a ball of weight 15 N is held in the hand. Find the sum of the moments about A (anticlockwise positive).
4
In the sign-arm example, what tension would make the moments about A balance exactly (sum 0)? (AB = 1.2 m, AC = 0.9 m, weight 45 N.)
5
Why does the hinge reaction not appear when we take moments about the hinge?